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anonymous

  • one year ago

how do I solve v=lwh sove for h

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  1. Nnesha
    • one year ago
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    cancel out the `lw` from right side how would you do that ? would add lw both sides subtract or divide ?

  2. anonymous
    • one year ago
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    can you show me how to cancel

  3. Nnesha
    • one year ago
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    ye it's l times w times h (multiplication ) to cancel out the lw from right you should apply opposite of `multiplication`

  4. Nnesha
    • one year ago
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    so divide both sides by lw

  5. Nnesha
    • one year ago
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    here is an example ab = y (solve for b) so i would divide both sides by a \[\huge\rm \frac{ \cancel{a}b }{ \cancel{a} }=\frac{ y }{ a }\]\ b=y/a

  6. anonymous
    • one year ago
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    Thank you. how do you solve 5/9(f-32) solve for f

  7. anonymous
    • one year ago
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    c=5/9

  8. Nnesha
    • one year ago
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    \[\huge\rm c=\frac{ 5 }{ 9 }(f-32)\] like this ?

  9. anonymous
    • one year ago
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    how do you solve for f

  10. Nnesha
    • one year ago
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    first of all move 5/9 to the left side so multiply both sides by 9/5 let me know what you get after this

  11. anonymous
    • one year ago
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    45/45

  12. Nnesha
    • one year ago
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    which is equal to what ? 45/45= ?

  13. anonymous
    • one year ago
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    1

  14. Nnesha
    • one year ago
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    yes right and you have to mutliply 9/5 `both` sides \[\huge\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ 5 }{ 9 }(f-32) \times \color{blue}{\frac{ 9 }{ 5 }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5}} \times c= \frac{ \cancel{5} }{\cancel{ 9} }(f-32) \times \color{blue}{\frac{\cancel{ 9} }{ \cancel{5} }}\]\[\large\rm \color{blue}{\frac{ 9 }{ 5 } }\times c =f-32\] now move -32 to the left side

  15. anonymous
    • one year ago
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    do I still have to add the rest of the equation. once I move -32 to the left

  16. Nnesha
    • one year ago
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    you have to add 32`both` sides

  17. anonymous
    • one year ago
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    im confused

  18. Nnesha
    • one year ago
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    hmm why ?

  19. anonymous
    • one year ago
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    because you said to add 32 on both sides. will that include the rest of the equation

  20. Nnesha
    • one year ago
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    solve for `f` right so you need to transfer all the numbers and variables to the left side 32 is negative at right side that's why we should add

  21. Nnesha
    • one year ago
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    yes right

  22. Nnesha
    • one year ago
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    |dw:1441637511242:dw|

  23. Nnesha
    • one year ago
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    so what would be ur final answer ?

  24. Nnesha
    • one year ago
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    let me know if u didn't understand :)

  25. anonymous
    • one year ago
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    um. 9c=37

  26. Nnesha
    • one year ago
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    how did you get 37 ? and who kidnapped 5 from left side ?

  27. anonymous
    • one year ago
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    I crossed out 32 from right side and added 5 + 32

  28. Nnesha
    • one year ago
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    you can't add 5+ 32 it's 9c/5 not just 5

  29. Nnesha
    • one year ago
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    |dw:1441637740316:dw|

  30. anonymous
    • one year ago
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    oh ok. so is there another step

  31. Nnesha
    • one year ago
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    nope that's it!

  32. anonymous
    • one year ago
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    so how did we solve for f

  33. Nnesha
    • one year ago
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    what do you get at right side when you add 32 ?

  34. anonymous
    • one year ago
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    64

  35. Nnesha
    • one year ago
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    how ??....

  36. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @aveena47 I crossed out 32 from right side \(\color{blue}{\text{End of Quote}}\) ^^^

  37. Nnesha
    • one year ago
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    |dw:1441638051059:dw| -32+32= ?

  38. anonymous
    • one year ago
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    o

  39. Nnesha
    • one year ago
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    yes right so what do you have left at right side ? left side) you can't combine 9c/5 with 32 bec they aren't `like` terms

  40. anonymous
    • one year ago
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    f

  41. Nnesha
    • one year ago
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    right.

  42. anonymous
    • one year ago
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    f=9c/5

  43. Nnesha
    • one year ago
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    what about the 32 left side ?

  44. anonymous
    • one year ago
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    f=9c/5+32

  45. Nnesha
    • one year ago
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    yes right!

  46. anonymous
    • one year ago
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    thanks

  47. anonymous
    • one year ago
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    ax+by=c solve for x

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