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anonymous

  • one year ago

how do you solve 4/15-3/5=x-4/3

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  1. Hero
    • one year ago
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    Multiply both sides by 15 to eliminate the denominators.

  2. anonymous
    • one year ago
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    how do you muliply both sides by 15

  3. Hero
    • one year ago
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    \(15\left(\dfrac{4}{15} - \dfrac{3}{5}\right) = 15\left(x - \dfrac{4}{3}\right)\)

  4. anonymous
    • one year ago
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    do i need to remove the parentheses

  5. Hero
    • one year ago
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    You can only remove the parentheses after apply the distributive rule.

  6. Hero
    • one year ago
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    \(15\left(\dfrac{4}{15}\right) - 15\left(\dfrac{3}{5}\right) = 15x - 15\left(\dfrac{4}{3}\right)\)

  7. anonymous
    • one year ago
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    still confused.

  8. texaschic101
    • one year ago
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    by multiplying both sides by the common denominator...this gets rid of the fractions

  9. anonymous
    • one year ago
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    15x=4/3

  10. texaschic101
    • one year ago
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    or you can do it with the fractions. 4/15 - 3/5 = x - 4/3 --- add 4/3 to both sides 4/15 - 3/5 + 4/3 = x now...to add/subtract fractions you need a common denominator. A number that all your denominators go into evenly. That would be 15. 4/15 = 4/15 -3/5 = - 9/15 4/3 = 20/15 now we re-write the problem 4/15 - 9/15 + 20/15 = x now do the math and what do you get ?

  11. anonymous
    • one year ago
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    43/15

  12. texaschic101
    • one year ago
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    (4 - 9 + 20) / 15 = x 15/15 = x 1 = x check.. 4/15 - 3/5 = x - 4/3 4/15 - 9/15 = 1 - 20/15 4/15 - 9/15 = 15/15 - 20/15 -5/15 = -5/15 (correct) so x = 1

  13. anonymous
    • one year ago
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    oh ok I see. Thank You

  14. texaschic101
    • one year ago
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    YW :)

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