anonymous
  • anonymous
how do you solve 4/15-3/5=x-4/3
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Hero
  • Hero
Multiply both sides by 15 to eliminate the denominators.
anonymous
  • anonymous
how do you muliply both sides by 15
Hero
  • Hero
\(15\left(\dfrac{4}{15} - \dfrac{3}{5}\right) = 15\left(x - \dfrac{4}{3}\right)\)

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anonymous
  • anonymous
do i need to remove the parentheses
Hero
  • Hero
You can only remove the parentheses after apply the distributive rule.
Hero
  • Hero
\(15\left(\dfrac{4}{15}\right) - 15\left(\dfrac{3}{5}\right) = 15x - 15\left(\dfrac{4}{3}\right)\)
anonymous
  • anonymous
still confused.
texaschic101
  • texaschic101
by multiplying both sides by the common denominator...this gets rid of the fractions
anonymous
  • anonymous
15x=4/3
texaschic101
  • texaschic101
or you can do it with the fractions. 4/15 - 3/5 = x - 4/3 --- add 4/3 to both sides 4/15 - 3/5 + 4/3 = x now...to add/subtract fractions you need a common denominator. A number that all your denominators go into evenly. That would be 15. 4/15 = 4/15 -3/5 = - 9/15 4/3 = 20/15 now we re-write the problem 4/15 - 9/15 + 20/15 = x now do the math and what do you get ?
anonymous
  • anonymous
43/15
texaschic101
  • texaschic101
(4 - 9 + 20) / 15 = x 15/15 = x 1 = x check.. 4/15 - 3/5 = x - 4/3 4/15 - 9/15 = 1 - 20/15 4/15 - 9/15 = 15/15 - 20/15 -5/15 = -5/15 (correct) so x = 1
anonymous
  • anonymous
oh ok I see. Thank You
texaschic101
  • texaschic101
YW :)

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