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anonymous

  • one year ago

How do you factor? Please Explain! 6r^2 -26r=16+8-7r

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  1. mattyboyy
    • one year ago
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    Combine like terms I belive

  2. rockindud
    • one year ago
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    6r^2-19r-24=0

  3. mattyboyy
    • one year ago
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    @rockindud how did you get zero?

  4. mattyboyy
    • one year ago
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    |dw:1441643619042:dw|

  5. mattyboyy
    • one year ago
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    Combine the like terms

  6. mattyboyy
    • one year ago
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    you have 26 r and -7r

  7. mattyboyy
    • one year ago
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    sorry -26r and -7r

  8. mattyboyy
    • one year ago
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    |dw:1441643772401:dw| You want to get rid of the numbers to the right

  9. mattyboyy
    • one year ago
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    |dw:1441643885198:dw| Thats what you should have right now

  10. mattyboyy
    • one year ago
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    You getting this?

  11. mattyboyy
    • one year ago
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    @rockindud Im not saying you're wrong btw I'm just thinking that the final equation would be 6^2 -19r = 24

  12. anonymous
    • one year ago
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    The equation should be 6r^2 -19r - 24 =0 for factorising @mattyboyy

  13. anonymous
    • one year ago
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    \[6\left( r^2-\frac{ 19 }{ 6 }r-4 \right)=0\] \[6\left( r^2-\frac{ 19 }{ 6 }r+\left( \frac{ -19 }{ 12 } \right)^2-\left( \frac{ -19 }{ 12 } \right)^2-4 \right)=0\]\[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\frac{ 361 }{ 144 }-4 \right\}=0\] \[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\frac{ 361+576 }{ 144 } \right\}=0\] \[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\left( \frac{ \sqrt{937} }{ 12 } \right)^2 \right\}=0\] \[6\left( r-\frac{ 19 }{ 12 }+\frac{ \sqrt{937} }{ 12 } \right)\left( r-\frac{ 19 }{ 12 }-\frac{ \sqrt{937} }{ 12 } \right)=0\]

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