anonymous
  • anonymous
How do you factor? Please Explain! 6r^2 -26r=16+8-7r
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mattyboyy
  • mattyboyy
Combine like terms I belive
rockindud
  • rockindud
6r^2-19r-24=0
mattyboyy
  • mattyboyy
@rockindud how did you get zero?

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mattyboyy
  • mattyboyy
|dw:1441643619042:dw|
mattyboyy
  • mattyboyy
Combine the like terms
mattyboyy
  • mattyboyy
you have 26 r and -7r
mattyboyy
  • mattyboyy
sorry -26r and -7r
mattyboyy
  • mattyboyy
|dw:1441643772401:dw| You want to get rid of the numbers to the right
mattyboyy
  • mattyboyy
|dw:1441643885198:dw| Thats what you should have right now
mattyboyy
  • mattyboyy
You getting this?
mattyboyy
  • mattyboyy
@rockindud Im not saying you're wrong btw I'm just thinking that the final equation would be 6^2 -19r = 24
anonymous
  • anonymous
The equation should be 6r^2 -19r - 24 =0 for factorising @mattyboyy
anonymous
  • anonymous
\[6\left( r^2-\frac{ 19 }{ 6 }r-4 \right)=0\] \[6\left( r^2-\frac{ 19 }{ 6 }r+\left( \frac{ -19 }{ 12 } \right)^2-\left( \frac{ -19 }{ 12 } \right)^2-4 \right)=0\]\[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\frac{ 361 }{ 144 }-4 \right\}=0\] \[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\frac{ 361+576 }{ 144 } \right\}=0\] \[6\left\{ \left( r-\frac{ 19 }{ 12 } \right)^2-\left( \frac{ \sqrt{937} }{ 12 } \right)^2 \right\}=0\] \[6\left( r-\frac{ 19 }{ 12 }+\frac{ \sqrt{937} }{ 12 } \right)\left( r-\frac{ 19 }{ 12 }-\frac{ \sqrt{937} }{ 12 } \right)=0\]

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