anonymous
  • anonymous
How do I solve Polynomial equations?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
3.2x^3+4.8x+3.7 2.1x^3+6.3x-2.9 --------------- ?
amistre64
  • amistre64
the sum of 2 polynomials is a polynomial ... you just add up like parts.
amistre64
  • amistre64
think of them as a hidden number, and the x parts determine the placement of a digit.

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anonymous
  • anonymous
So the 3.2x^3 over 2.1x^3 part is 3.3x^9?
amistre64
  • amistre64
assuming that we are adding them to start with ... almost. x^3 is a common factor; like 3a + 2a = (3+2)a, not 5a^2
amistre64
  • amistre64
3.2x^3 + 2.1x^3 = (3.2 + 2.1)x^3
anonymous
  • anonymous
but how would i write that on a graph? it's just boxes i place the digits in.
amistre64
  • amistre64
im not sure what you mean by that
amistre64
  • amistre64
can you post a picture of your problem?
anonymous
  • anonymous
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amistre64
  • amistre64
yeah, you are just adding like parts ...
amistre64
  • amistre64
what is 3.2 + 2.1 ?
anonymous
  • anonymous
just the first part of the equation. what would the answer look like?
amistre64
  • amistre64
what is 3.2 + 2.1 ?
anonymous
  • anonymous
5.3 lol...
amistre64
  • amistre64
then we can work it as: \[3.2x^3 + 2.1x^3 = (\color{red}{3.2 + 2.1})x^3=\color{red}{5.3}x^3\]
anonymous
  • anonymous
ok. i think i might have it. just give me a second.
amistre64
  • amistre64
k
anonymous
  • anonymous
ok so i hav it this far. look right so far? what symbols would i use? (+/-)
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amistre64
  • amistre64
is 6+4 a positive or negative number?
anonymous
  • anonymous
positive?
amistre64
  • amistre64
then that ones a + is 3.7-2.9 a positive or negative number?
anonymous
  • anonymous
positive? 0.8
amistre64
  • amistre64
yes, so its a + the operation symbol just indicates the sign of the resulting operation you did on the numbers. a postive result gives us + a negative result gives us -
anonymous
  • anonymous
Ok. Thank you so much! It seems kinda easy now that I know how it's done. Thanks!
amistre64
  • amistre64
good luck :)

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