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anonymous

  • one year ago

When 0.054 moles of aluminum sulfate are dissolved in enough water to make 459 milliliters of solution, what is the molarity of sulfate ions? Answer in units of M.

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  1. anonymous
    • one year ago
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    Molarity = moles of solute (aluminum sulfate) divided by the volume of the solution in L. So, to calculate the molarity, divide the moles of aluminum sulfate by the volume of solution in L.

  2. Jhannybean
    • one year ago
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    \[\sf \frac{0.054 ~mol~Al_2(SO_4)_3}{459~mL~soln}~\times ~ \frac{1~mL}{10^{-3}~L~ soln}~\times \frac{3~mol~SO_4^{2+}~ions}{1~mol~Al_2(SO_4)_3}\]\[\sf=\frac{(0.054 \cdot 3)~ mol~ SO_4^{2+} ~ions}{(459 \cdot 10^{-3}) ~L~ soln} \]\[=~?\]

  3. anonymous
    • one year ago
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    .4 or .35 or .353 ??? depending on what you used for sig figs? @Jhannybean

  4. Jhannybean
    • one year ago
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    The answer I got was: \[\sf \frac{0.35 ~mol~ SO_$^{2+}~ions }{1~L~soln}\] 2 sig figs because you started with 0.054 moles aluminum sulfate

  5. anonymous
    • one year ago
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    thanks so much!!!!

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