anonymous
  • anonymous
When 0.054 moles of aluminum sulfate are dissolved in enough water to make 459 milliliters of solution, what is the molarity of sulfate ions? Answer in units of M.
Chemistry
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Molarity = moles of solute (aluminum sulfate) divided by the volume of the solution in L. So, to calculate the molarity, divide the moles of aluminum sulfate by the volume of solution in L.
Jhannybean
  • Jhannybean
\[\sf \frac{0.054 ~mol~Al_2(SO_4)_3}{459~mL~soln}~\times ~ \frac{1~mL}{10^{-3}~L~ soln}~\times \frac{3~mol~SO_4^{2+}~ions}{1~mol~Al_2(SO_4)_3}\]\[\sf=\frac{(0.054 \cdot 3)~ mol~ SO_4^{2+} ~ions}{(459 \cdot 10^{-3}) ~L~ soln} \]\[=~?\]
anonymous
  • anonymous
.4 or .35 or .353 ??? depending on what you used for sig figs? @Jhannybean

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Jhannybean
  • Jhannybean
The answer I got was: \[\sf \frac{0.35 ~mol~ SO_$^{2+}~ions }{1~L~soln}\] 2 sig figs because you started with 0.054 moles aluminum sulfate
anonymous
  • anonymous
thanks so much!!!!

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