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amy0799

  • one year ago

find derivative of the algebraic function

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  1. amy0799
    • one year ago
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    \[f(x)=x ^{5}(1-\frac{ 6 }{ x+5 })\]

  2. welshfella
    • one year ago
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    first expand the bracket - find derivative of x^5 then use the quotient rule to differentiate the fraction

  3. amy0799
    • one year ago
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    c\[\frac{ x ^{5} (x-1)}{ x+5 }\] can I do this?

  4. welshfella
    • one year ago
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    or if you prefer you can use the product / chain rules

  5. welshfella
    • one year ago
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    how did you get that?

  6. madhu.mukherjee.946
    • one year ago
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    i think he took the lcm

  7. amy0799
    • one year ago
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    \[1-\left( \frac{ 6 }{ x+5 } \right) = \frac{ x-1 }{ x+5 }\]

  8. madhu.mukherjee.946
    • one year ago
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    correct

  9. amy0799
    • one year ago
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    so then \[\frac{ x ^{6}-x ^{5} }{ x+5 }\] I would just use the quotient rule?

  10. welshfella
    • one year ago
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    yes

  11. amy0799
    • one year ago
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    the answer would be \[f'(x)=\frac{ 5x ^{6}+26x ^{5}-25x ^{4} }{ (x+5)^{2}}\]?

  12. madhu.mukherjee.946
    • one year ago
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    correct

  13. madhu.mukherjee.946
    • one year ago
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    :)

  14. welshfella
    • one year ago
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    yes i get that too

  15. amy0799
    • one year ago
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    cool thanks!

  16. welshfella
    • one year ago
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    I'm slowing up in my old age lol!

  17. madhu.mukherjee.946
    • one year ago
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    @amy0799 thats really nice

  18. welshfella
    • one year ago
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    yes

  19. welshfella
    • one year ago
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    looking at it again I would have used the product rule because the algebra is easier...

  20. madhu.mukherjee.946
    • one year ago
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    @welshfella its okay:)

  21. welshfella
    • one year ago
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    lol - it has to be..

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