anonymous
  • anonymous
I have an aluminum cylinder; length =10cm and radius =.25cm density of aluminum =2.70g/cm3 1Al atom =4.48*10-23g How many Al Atoms are in the cylinder? Would you find the volume first? then do mass = d*v? and divide that by the mass of 1 Al atom?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@toxicsugar22 do you know?
anonymous
  • anonymous
@3-sfera doing what i explained in the question i got 1.18*10^23 atoms of Al, do you know if i did this correctly
anonymous
  • anonymous
let me do some math

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anonymous
  • anonymous
no my result is 1,2x10^27
anonymous
  • anonymous
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anonymous
  • anonymous
i did Vcylinder = pi r^2(h) pi(.25^2)(10) = 1.96cm^3 then mass = d*v m= 2.70*1.96 = 5.292 then 5.292 / 4.48*10^-23 = 1.18*10^23
anonymous
  • anonymous
in the question it says taht 1 atom of Al = 4.48 * 10^-23 g
anonymous
  • anonymous
my solution is with the molar mass, your volume is incorrect i think. the volume is 1,96*10^3 cm^3
anonymous
  • anonymous
so my number of atoms is correct too? 1.18*10^23
anonymous
  • anonymous
uhm actually not :).. maybe just some different approximation..maybe the mass on your book is wromg
anonymous
  • anonymous
Well by the book, the answer is correct then?
anonymous
  • anonymous
@aaronq can you please help?
anonymous
  • anonymous
the answer with your atom mass is 1.8*10^26
anonymous
  • anonymous
sorry for late i'm a little bit busy
anonymous
  • anonymous
i don't understand how you got that.
anonymous
  • anonymous
oh flutter wait.. the radius is 0.25
anonymous
  • anonymous
*flutter
anonymous
  • anonymous
ahha i wanna write f*u*c*k but it shows flutter
anonymous
  • anonymous
by the way, i misread the radius
anonymous
  • anonymous
your answer is correct i think
anonymous
  • anonymous
sorry @Savannah_Lynn13

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