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pooja195

  • one year ago

Can some please explain how to do #37 to me.... i'm not really sure how. http://prntscr.com/8dqn9t

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  1. Hero
    • one year ago
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    @pooja195, do you remember the acronym for congruent triangles?

  2. pooja195
    • one year ago
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    No :/

  3. Hero
    • one year ago
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    You don't remember what CPCTC stands for?

  4. pooja195
    • one year ago
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    Corresponding parts of a triangle are congruent...? right?

  5. Hero
    • one year ago
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    Correct, Corresponding parts of congruent triangles are congruent. What do you think this means for \(\triangle{ABC} \cong \triangle{DEF}\) ?

  6. pooja195
    • one year ago
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    that equal sign with the squiggly thingy means that they correspond so triangle ABC corresponds to triangle DEF?

  7. dan815
    • one year ago
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    it means congruent or equal trinagles

  8. pooja195
    • one year ago
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    same thing -.-

  9. Hero
    • one year ago
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    Well, @pooja195, here's a bit of insight for you: \(\triangle{ABC} \cong \triangle{DEF}\) means the following: \(\angle{A} \cong \angle{D}\) \(\angle{B} \cong \angle{E}\) \(\angle{C} \cong \angle{F}\) \(\overline{AB} \cong \overline{DE}\) \(\overline{BC} \cong \overline{EF}\) \(\overline{AC} \cong \overline{DF}\)

  10. pooja195
    • one year ago
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    this is confusing... :/

  11. Hero
    • one year ago
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    The corresponding angles have the same measure and the corresponding segments have the same length.

  12. pooja195
    • one year ago
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    So DEF is 5?

  13. Hero
    • one year ago
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    I think what you meant to say is that since \(\overline{AC} = 5\) then \(\overline{DF} = 5\)

  14. Hero
    • one year ago
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    @pooja195, what does the problem ask us to find?

  15. pooja195
    • one year ago
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    Find DF and m<B

  16. Hero
    • one year ago
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    Okay, and we found \(\overline{DF}\). Now we have to find \(m\angle{B}\). Any ideas on that at all based on what was explained above?

  17. pooja195
    • one year ago
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    B and E are congruent

  18. Hero
    • one year ago
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    B and E correspond with each other and therefore have the same measure.

  19. pooja195
    • one year ago
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    so 100 degrees?

  20. Hero
    • one year ago
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    \(m\angle{E} = 100^{\circ}\), therefore \(m\angle{B} = 100^{\circ}\). That's how you would say it properly. Saying just "100 degrees" isn't really saying anything other than just "announcing" 100 degrees. Somebody might think you're referring to the temperature outside.

  21. pooja195
    • one year ago
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    Aight thanks :)

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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