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amurciano2
 one year ago
How would you dinghies question. I have the work, but I can't find a mistake.
amurciano2
 one year ago
How would you dinghies question. I have the work, but I can't find a mistake.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441657409641:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You must use cos (2t) = 12sin^2 t so that sin^2 t = (1/2)  (cos (2t))/2 to plug in the integral. One more thing: if you let x = 2 sin t, then t = arcsin(x/2) , the limits change also when x = 0 , t = ...., x =1 , t=.... Replace all to work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't forget, if x from 0 to 1, t < pi/2

amurciano2
 one year ago
Best ResponseYou've already chosen the best response.0We're did you get the cos(2t) from?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://www.purplemath.com/modules/idents.htm at "double angles identity"

amurciano2
 one year ago
Best ResponseYou've already chosen the best response.0Where is the double identity in the work?

amurciano2
 one year ago
Best ResponseYou've already chosen the best response.0I see it. Thank you!!!!

amurciano2
 one year ago
Best ResponseYou've already chosen the best response.0I retried it. Do you still find a mistake?

amurciano2
 one year ago
Best ResponseYou've already chosen the best response.0I found one mistake. The answer is till not right though. :(
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