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anonymous
 one year ago
Complete the following statement.
anonymous
 one year ago
Complete the following statement.

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\LARGE\color{black}{ f(x) = \begin{cases} & x^2+2,{~~~~}{\large x\le1} \\ & ax,{~~~~~~~~~~}{\large x>1} \end{cases} }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2So, you want that \(x^2+2\), at \(x=1\), will be equivalent to \(ax\), at \(x=1\).

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\large\color{black}{ \displaystyle (1)^2+2=a(1) }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2a times 1 is just 1. and: (1)²+2=1+2=3

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2So the value of a that you want is equal to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To the value in x^2 + 2?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2Again, you want \(ax\) and \(x^2+2\) to be equal at x=1, so that there is no discontinuity at x=1.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\large x^2+2=ax\) \(\large 1^2+2=a\cdot 1\) \(\large {~~~~~~~}a~=~?\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01^2+2=3 3 * 1 = 3 a = 3 right? :)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2I didn't see that reply. I glitched. Again, yes you are right, a=3.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for teaching me :)
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