a 500-kg load is supported by a pair of hingeless legs as shown below. There is no friction between the legs and the floor. Find the tension in the rope.
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This question entails finding the resulting weight dispersed onto two different legs at equal angles using trigonometry. At first may seem slightly out of hand but as you get at it everything gets easier.
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I believe 500kg is a calculated weight.
how did you get that? like which formula?
Excuse me mass is usually expressed in kg so consider 500kg as the mass upon which you have to impose 9.8m/s^2 to get the corresponding newton's force.
500kg*9.8m/s^2=corresponding newtons force
thank you so much
Now the resulting Newton's force is perpendicular to the ground with frictionless surface so take the newton's force to the perpendicular as the "bisector" of the triangle which makes 2 triangles with a same angle of 65 degrees on each side.
Now use the appropriate trigonometry to calculate the corresponding force on the hypotenuse, and then find the base from the bisector to calculate the force pulling towards opposite direction. Now multiply that force on the bottom of the one half of the triangle by a factor of 2 to get the tension force acting on the string keeping the structure from collapsing.