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TinaSh
 one year ago
a 500kg load is supported by a pair of hingeless legs as shown below. There is no friction between the legs and the floor. Find the tension in the rope.
TinaSh
 one year ago
a 500kg load is supported by a pair of hingeless legs as shown below. There is no friction between the legs and the floor. Find the tension in the rope.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This question entails finding the resulting weight dispersed onto two different legs at equal angles using trigonometry. At first may seem slightly out of hand but as you get at it everything gets easier.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I believe 500kg is a calculated weight.

TinaSh
 one year ago
Best ResponseYou've already chosen the best response.0how did you get that? like which formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excuse me mass is usually expressed in kg so consider 500kg as the mass upon which you have to impose 9.8m/s^2 to get the corresponding newton's force.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0500kg*9.8m/s^2=corresponding newtons force

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now the resulting Newton's force is perpendicular to the ground with frictionless surface so take the newton's force to the perpendicular as the "bisector" of the triangle which makes 2 triangles with a same angle of 65 degrees on each side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now use the appropriate trigonometry to calculate the corresponding force on the hypotenuse, and then find the base from the bisector to calculate the force pulling towards opposite direction. Now multiply that force on the bottom of the one half of the triangle by a factor of 2 to get the tension force acting on the string keeping the structure from collapsing.
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