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I'm understanding them better but I still don't know what to do with the -2 part.

are you doing long division?

Probably. Is that how the answer is normally found?

sometimes. when you can factor, that way's easier, but it doesn't look like this factors easily

Ok. So how is the long division done?

|dw:1441661061285:dw|

Oh I see! But do I subtract 6x^3 - 4x^2? Or 11x^2-4x^2?

subtract like terms, so \(6x^3 - 6x^3\) and \(11x^2-(-4x^2)\)

like terms is the exponent right? subtract ^2's with ^2's?

yep

so then i get 7x^2 and divide that by 3x-2 all over again?

Now you start over again by dividing \[\frac{ 15x^2 }{ 3x }\]

ok 15 makes more sense lol

yeah, most times the numbers will be nice to work with, so that's usually a good check

exactly

yay! thank you so much!

you're welcome. tag me if you want the answer checked

|dw:1441662259557:dw| um but is it supposed to completely lose the x?

The 10 is supposed to be 10x, so then when you subtract you should have positive 6

so 6x or 6?

6x

ok. i'll post my answer in a bit.

ok.

2x^2+5x+2x?

2x^2+5x+2
There shouldn't be an x on the last 2.

ok

|dw:1441662698472:dw|

yup that's what i've got. thanks!

you're welcome :) are you just supposed to divide this, like do they ask anything else?

the answer must be like ax^2+bx +c cuz is degree Numerator 3 and denumerator degree 1 @xFeathertailx

if was mod 0

sorry i forget

ok, that's the answer then xD

yup

yes

trying to get the pic.

well it's
2x^2+4x+5
x-2|2x^2+x+3
2x^2-4x
4x 3
4x-8
-5

i think soomething went wrong. it's supposed to fit into

|dw:1441663943278:dw|

It looks like the 2x² you have on top should be 2x.
Then you subtracted the x terms wrong

ok. isee that now. but ho w does it fit into the grid i showed you?

|dw:1441664318011:dw|
So the solution is
\[2x+5+\frac{ 7 }{ x-2 }\]

I love this site! So many helpful people!

lol. glad to help