More Polynomials ugh...
(6x^3+11x^2-4x-4)/3x-2

- anonymous

More Polynomials ugh...
(6x^3+11x^2-4x-4)/3x-2

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- jamiebookeater

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- anonymous

I'm understanding them better but I still don't know what to do with the -2 part.

- anonymous

are you doing long division?

- anonymous

Probably. Is that how the answer is normally found?

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## More answers

- anonymous

sometimes. when you can factor, that way's easier, but it doesn't look like this factors easily

- anonymous

Ok. So how is the long division done?

- anonymous

|dw:1441661061285:dw|

- anonymous

i have it written like that, but how is it done? I'm bad at math so i need it explained step by step.

- anonymous

start off by dividing 6x² by 3x
\[\frac{ 6x^2 }{ 3x }=2x^2\]
then write 2x above the division sign and multiply it by (3x-2)
\[2x^2(3x-2)=6x^3-4x^2\]
then subtract
|dw:1441661304727:dw|

- anonymous

Oh I see! But do I subtract 6x^3 - 4x^2? Or 11x^2-4x^2?

- anonymous

subtract like terms, so \(6x^3 - 6x^3\) and \(11x^2-(-4x^2)\)

- anonymous

like terms is the exponent right? subtract ^2's with ^2's?

- anonymous

yep

- anonymous

so then i get 7x^2 and divide that by 3x-2 all over again?

- anonymous

no it's 11-(-4), so that's -15
then it's like this once you drop the other terms down
|dw:1441661731441:dw|

- anonymous

Now you start over again by dividing \[\frac{ 15x^2 }{ 3x }\]

- anonymous

ok 15 makes more sense lol

- anonymous

yeah, most times the numbers will be nice to work with, so that's usually a good check

- anonymous

I'm writing it all on paper and I think I see the pattern now. It's slowly losing the exponent one power at a time?

- anonymous

exactly

- anonymous

yay! thank you so much!

- anonymous

you're welcome. tag me if you want the answer checked

- anonymous

|dw:1441662259557:dw| um but is it supposed to completely lose the x?

- anonymous

@peachpi

- anonymous

The 10 is supposed to be 10x, so then when you subtract you should have positive 6

- anonymous

so 6x or 6?

- anonymous

6x

- anonymous

ok. i'll post my answer in a bit.

- anonymous

ok.

- anonymous

2x^2+5x+2x?

- anonymous

2x^2+5x+2
There shouldn't be an x on the last 2.

- anonymous

ok

- anonymous

|dw:1441662698472:dw|

- anonymous

yup that's what i've got. thanks!

- anonymous

you're welcome :) are you just supposed to divide this, like do they ask anything else?

- dinamix

the answer must be like ax^2+bx +c cuz is degree Numerator 3 and denumerator degree 1 @xFeathertailx

- anonymous

nope, it doesn't give any instruction other than putting it in descending power of x. just a space to put the answer.

- dinamix

if was mod 0

- dinamix

sorry i forget

- anonymous

ok, that's the answer then xD

- dinamix

yup

- dinamix

good explain @peachpi

- anonymous

one more question. ae you sill here @peachpi ?

- anonymous

or @dinamix

- anonymous

yes

- anonymous

trying to get the pic.

- anonymous

well it's
2x^2+4x+5
x-2|2x^2+x+3
2x^2-4x
4x 3
4x-8
-5

- anonymous

i think soomething went wrong. it's supposed to fit into

##### 1 Attachment

- anonymous

|dw:1441663943278:dw|

- anonymous

It looks like the 2x² you have on top should be 2x.
Then you subtracted the x terms wrong

- anonymous

ok. isee that now. but ho w does it fit into the grid i showed you?

- anonymous

|dw:1441664318011:dw|
So the solution is
\[2x+5+\frac{ 7 }{ x-2 }\]

- anonymous

Oh!!! Because the ^2 shouldn't have been there and the remainder goes above the bar? Now that makes sense!!!

- anonymous

I love this site! So many helpful people!

- anonymous

lol. glad to help

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