More Polynomials ugh... (6x^3+11x^2-4x-4)/3x-2

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More Polynomials ugh... (6x^3+11x^2-4x-4)/3x-2

Mathematics
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I'm understanding them better but I still don't know what to do with the -2 part.
are you doing long division?
Probably. Is that how the answer is normally found?

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sometimes. when you can factor, that way's easier, but it doesn't look like this factors easily
Ok. So how is the long division done?
|dw:1441661061285:dw|
i have it written like that, but how is it done? I'm bad at math so i need it explained step by step.
start off by dividing 6x² by 3x \[\frac{ 6x^2 }{ 3x }=2x^2\] then write 2x above the division sign and multiply it by (3x-2) \[2x^2(3x-2)=6x^3-4x^2\] then subtract |dw:1441661304727:dw|
Oh I see! But do I subtract 6x^3 - 4x^2? Or 11x^2-4x^2?
subtract like terms, so \(6x^3 - 6x^3\) and \(11x^2-(-4x^2)\)
like terms is the exponent right? subtract ^2's with ^2's?
yep
so then i get 7x^2 and divide that by 3x-2 all over again?
no it's 11-(-4), so that's -15 then it's like this once you drop the other terms down |dw:1441661731441:dw|
Now you start over again by dividing \[\frac{ 15x^2 }{ 3x }\]
ok 15 makes more sense lol
yeah, most times the numbers will be nice to work with, so that's usually a good check
I'm writing it all on paper and I think I see the pattern now. It's slowly losing the exponent one power at a time?
exactly
yay! thank you so much!
you're welcome. tag me if you want the answer checked
|dw:1441662259557:dw| um but is it supposed to completely lose the x?
The 10 is supposed to be 10x, so then when you subtract you should have positive 6
so 6x or 6?
6x
ok. i'll post my answer in a bit.
ok.
2x^2+5x+2x?
2x^2+5x+2 There shouldn't be an x on the last 2.
ok
|dw:1441662698472:dw|
yup that's what i've got. thanks!
you're welcome :) are you just supposed to divide this, like do they ask anything else?
the answer must be like ax^2+bx +c cuz is degree Numerator 3 and denumerator degree 1 @xFeathertailx
nope, it doesn't give any instruction other than putting it in descending power of x. just a space to put the answer.
if was mod 0
sorry i forget
ok, that's the answer then xD
yup
good explain @peachpi
one more question. ae you sill here @peachpi ?
yes
trying to get the pic.
well it's 2x^2+4x+5 x-2|2x^2+x+3 2x^2-4x 4x 3 4x-8 -5
i think soomething went wrong. it's supposed to fit into
1 Attachment
|dw:1441663943278:dw|
It looks like the 2x² you have on top should be 2x. Then you subtracted the x terms wrong
ok. isee that now. but ho w does it fit into the grid i showed you?
|dw:1441664318011:dw| So the solution is \[2x+5+\frac{ 7 }{ x-2 }\]
Oh!!! Because the ^2 shouldn't have been there and the remainder goes above the bar? Now that makes sense!!!
I love this site! So many helpful people!
lol. glad to help

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