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anonymous

  • one year ago

More Polynomials ugh... (6x^3+11x^2-4x-4)/3x-2

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  1. anonymous
    • one year ago
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    I'm understanding them better but I still don't know what to do with the -2 part.

  2. anonymous
    • one year ago
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    are you doing long division?

  3. anonymous
    • one year ago
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    Probably. Is that how the answer is normally found?

  4. anonymous
    • one year ago
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    sometimes. when you can factor, that way's easier, but it doesn't look like this factors easily

  5. anonymous
    • one year ago
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    Ok. So how is the long division done?

  6. anonymous
    • one year ago
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    |dw:1441661061285:dw|

  7. anonymous
    • one year ago
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    i have it written like that, but how is it done? I'm bad at math so i need it explained step by step.

  8. anonymous
    • one year ago
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    start off by dividing 6x² by 3x \[\frac{ 6x^2 }{ 3x }=2x^2\] then write 2x above the division sign and multiply it by (3x-2) \[2x^2(3x-2)=6x^3-4x^2\] then subtract |dw:1441661304727:dw|

  9. anonymous
    • one year ago
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    Oh I see! But do I subtract 6x^3 - 4x^2? Or 11x^2-4x^2?

  10. anonymous
    • one year ago
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    subtract like terms, so \(6x^3 - 6x^3\) and \(11x^2-(-4x^2)\)

  11. anonymous
    • one year ago
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    like terms is the exponent right? subtract ^2's with ^2's?

  12. anonymous
    • one year ago
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    yep

  13. anonymous
    • one year ago
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    so then i get 7x^2 and divide that by 3x-2 all over again?

  14. anonymous
    • one year ago
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    no it's 11-(-4), so that's -15 then it's like this once you drop the other terms down |dw:1441661731441:dw|

  15. anonymous
    • one year ago
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    Now you start over again by dividing \[\frac{ 15x^2 }{ 3x }\]

  16. anonymous
    • one year ago
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    ok 15 makes more sense lol

  17. anonymous
    • one year ago
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    yeah, most times the numbers will be nice to work with, so that's usually a good check

  18. anonymous
    • one year ago
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    I'm writing it all on paper and I think I see the pattern now. It's slowly losing the exponent one power at a time?

  19. anonymous
    • one year ago
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    exactly

  20. anonymous
    • one year ago
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    yay! thank you so much!

  21. anonymous
    • one year ago
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    you're welcome. tag me if you want the answer checked

  22. anonymous
    • one year ago
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    |dw:1441662259557:dw| um but is it supposed to completely lose the x?

  23. anonymous
    • one year ago
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    @peachpi

  24. anonymous
    • one year ago
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    The 10 is supposed to be 10x, so then when you subtract you should have positive 6

  25. anonymous
    • one year ago
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    so 6x or 6?

  26. anonymous
    • one year ago
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    6x

  27. anonymous
    • one year ago
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    ok. i'll post my answer in a bit.

  28. anonymous
    • one year ago
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    ok.

  29. anonymous
    • one year ago
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    2x^2+5x+2x?

  30. anonymous
    • one year ago
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    2x^2+5x+2 There shouldn't be an x on the last 2.

  31. anonymous
    • one year ago
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    ok

  32. anonymous
    • one year ago
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    |dw:1441662698472:dw|

  33. anonymous
    • one year ago
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    yup that's what i've got. thanks!

  34. anonymous
    • one year ago
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    you're welcome :) are you just supposed to divide this, like do they ask anything else?

  35. dinamix
    • one year ago
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    the answer must be like ax^2+bx +c cuz is degree Numerator 3 and denumerator degree 1 @xFeathertailx

  36. anonymous
    • one year ago
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    nope, it doesn't give any instruction other than putting it in descending power of x. just a space to put the answer.

  37. dinamix
    • one year ago
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    if was mod 0

  38. dinamix
    • one year ago
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    sorry i forget

  39. anonymous
    • one year ago
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    ok, that's the answer then xD

  40. dinamix
    • one year ago
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    yup

  41. dinamix
    • one year ago
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    good explain @peachpi

  42. anonymous
    • one year ago
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    one more question. ae you sill here @peachpi ?

  43. anonymous
    • one year ago
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    or @dinamix

  44. anonymous
    • one year ago
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    yes

  45. anonymous
    • one year ago
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    trying to get the pic.

  46. anonymous
    • one year ago
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    well it's 2x^2+4x+5 x-2|2x^2+x+3 2x^2-4x 4x 3 4x-8 -5

  47. anonymous
    • one year ago
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    i think soomething went wrong. it's supposed to fit into

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  48. anonymous
    • one year ago
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    |dw:1441663943278:dw|

  49. anonymous
    • one year ago
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    It looks like the 2x² you have on top should be 2x. Then you subtracted the x terms wrong

  50. anonymous
    • one year ago
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    ok. isee that now. but ho w does it fit into the grid i showed you?

  51. anonymous
    • one year ago
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    |dw:1441664318011:dw| So the solution is \[2x+5+\frac{ 7 }{ x-2 }\]

  52. anonymous
    • one year ago
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    Oh!!! Because the ^2 shouldn't have been there and the remainder goes above the bar? Now that makes sense!!!

  53. anonymous
    • one year ago
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    I love this site! So many helpful people!

  54. anonymous
    • one year ago
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    lol. glad to help

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