## anonymous one year ago More Polynomials ugh... (6x^3+11x^2-4x-4)/3x-2

1. anonymous

I'm understanding them better but I still don't know what to do with the -2 part.

2. anonymous

are you doing long division?

3. anonymous

Probably. Is that how the answer is normally found?

4. anonymous

sometimes. when you can factor, that way's easier, but it doesn't look like this factors easily

5. anonymous

Ok. So how is the long division done?

6. anonymous

|dw:1441661061285:dw|

7. anonymous

i have it written like that, but how is it done? I'm bad at math so i need it explained step by step.

8. anonymous

start off by dividing 6x² by 3x $\frac{ 6x^2 }{ 3x }=2x^2$ then write 2x above the division sign and multiply it by (3x-2) $2x^2(3x-2)=6x^3-4x^2$ then subtract |dw:1441661304727:dw|

9. anonymous

Oh I see! But do I subtract 6x^3 - 4x^2? Or 11x^2-4x^2?

10. anonymous

subtract like terms, so $$6x^3 - 6x^3$$ and $$11x^2-(-4x^2)$$

11. anonymous

like terms is the exponent right? subtract ^2's with ^2's?

12. anonymous

yep

13. anonymous

so then i get 7x^2 and divide that by 3x-2 all over again?

14. anonymous

no it's 11-(-4), so that's -15 then it's like this once you drop the other terms down |dw:1441661731441:dw|

15. anonymous

Now you start over again by dividing $\frac{ 15x^2 }{ 3x }$

16. anonymous

ok 15 makes more sense lol

17. anonymous

yeah, most times the numbers will be nice to work with, so that's usually a good check

18. anonymous

I'm writing it all on paper and I think I see the pattern now. It's slowly losing the exponent one power at a time?

19. anonymous

exactly

20. anonymous

yay! thank you so much!

21. anonymous

you're welcome. tag me if you want the answer checked

22. anonymous

|dw:1441662259557:dw| um but is it supposed to completely lose the x?

23. anonymous

@peachpi

24. anonymous

The 10 is supposed to be 10x, so then when you subtract you should have positive 6

25. anonymous

so 6x or 6?

26. anonymous

6x

27. anonymous

ok. i'll post my answer in a bit.

28. anonymous

ok.

29. anonymous

2x^2+5x+2x?

30. anonymous

2x^2+5x+2 There shouldn't be an x on the last 2.

31. anonymous

ok

32. anonymous

|dw:1441662698472:dw|

33. anonymous

yup that's what i've got. thanks!

34. anonymous

you're welcome :) are you just supposed to divide this, like do they ask anything else?

35. dinamix

the answer must be like ax^2+bx +c cuz is degree Numerator 3 and denumerator degree 1 @xFeathertailx

36. anonymous

nope, it doesn't give any instruction other than putting it in descending power of x. just a space to put the answer.

37. dinamix

if was mod 0

38. dinamix

sorry i forget

39. anonymous

ok, that's the answer then xD

40. dinamix

yup

41. dinamix

good explain @peachpi

42. anonymous

one more question. ae you sill here @peachpi ?

43. anonymous

or @dinamix

44. anonymous

yes

45. anonymous

trying to get the pic.

46. anonymous

well it's 2x^2+4x+5 x-2|2x^2+x+3 2x^2-4x 4x 3 4x-8 -5

47. anonymous

i think soomething went wrong. it's supposed to fit into

48. anonymous

|dw:1441663943278:dw|

49. anonymous

It looks like the 2x² you have on top should be 2x. Then you subtracted the x terms wrong

50. anonymous

ok. isee that now. but ho w does it fit into the grid i showed you?

51. anonymous

|dw:1441664318011:dw| So the solution is $2x+5+\frac{ 7 }{ x-2 }$

52. anonymous

Oh!!! Because the ^2 shouldn't have been there and the remainder goes above the bar? Now that makes sense!!!

53. anonymous

I love this site! So many helpful people!

54. anonymous

lol. glad to help