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anonymous

  • one year ago

whats z^2z^4/z^3Z^-1

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  1. anonymous
    • one year ago
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    \[z ^{2} z ^{4}/z ^{3}z ^{-1}\]

  2. dinamix
    • one year ago
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    \[z^2z^4/z^3z ^{-1}= z^1/z^3 = 1/z^2\]

  3. dinamix
    • one year ago
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    u study number complexe

  4. anonymous
    • one year ago
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    how did you get z^1 on the top and z^3 on the bottom?

  5. anonymous
    • one year ago
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    @dinamix

  6. anonymous
    • one year ago
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    isn't it 2+4 which is 6 and the 3+ (-1)=2

  7. dinamix
    • one year ago
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    z^4/z^3 = Z^(4-3) = Z^1

  8. anonymous
    • one year ago
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    how're you getting those numbers though

  9. dinamix
    • one year ago
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    and z^2/z^-1 = z^(2-(-1)) =z^3

  10. anonymous
    • one year ago
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    ohhh okay i see what you did there! this problem was so easy but it wars confusing for second thanks for your help

  11. dinamix
    • one year ago
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    its when u see Basis of divided like this u have make difference

  12. dinamix
    • one year ago
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    \[z^x * z^y = z ^{x+y}\]

  13. dinamix
    • one year ago
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    \[z^x/z^y = z^{x-y}\]

  14. dinamix
    • one year ago
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    @Anzhbar

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