I have a calculus / derivative problem that I am unable to understand how the last step is worked out. The problem is
working it out I get:
(2x-5)^3 [2(1-x^4)(-4x^3)] + (1-x^4)^2 [3(2x-5)^2 (2)]
The online guide says to now factor and ends up with
I am unable to see what was factored and how the final answer was arrived at. Any help is appreciated. Straight answers are best. Asking me to try and guess is frustrating to me. Thanks
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
\[y=(2x-5)^3(1-x^4)^2\]And you're trying to take the derivative of this using the product rule - \(f'g + g'f\)?
\[(2x-5)^3 [2(1-x^4)(-4x^3)] + (1-x^4)^2 [3(2x-5)^2 (2)]\]
and they want
i meant this by the suggestion: write (2x-5) as A and (1-x^4) as B
with the simplifications, they want
\(= 2A^3B(-4x^3) + 3A^2 B^2\)
\(= 2A^2B(A(-8x^3) + 6B)\)
there's no silver bullet for this kind of mess. just look up at this thread!
that was just a suggestion as to how to make life easier. i am sure you can think of your own :p