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anonymous
 one year ago
Give the values of A and B for the function f(x)={AxB when x<=1, 24x when 1<x<5, Bx^2A when x>= 5} to be continuous at both x = 1 and x = 5.
anonymous
 one year ago
Give the values of A and B for the function f(x)={AxB when x<=1, 24x when 1<x<5, Bx^2A when x>= 5} to be continuous at both x = 1 and x = 5.

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.3this is not as hard as it may look replace \(x\) by \(1\) in both expressions \[AxB\] and \[24x\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3if \(x=1\)the first one is \(AB\) and the second is \(24\) so you have on equation \[AB=24\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3then put in \(x=5\) in both \(24x\) and \(Bx^2A\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3this time you get \[120=25BA\] as a second equation

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3solve the system \[AB=24\\25BA=120\] to find \(A\) and \(B\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much! I got that A= 30 and B=6. I'm just going to plug them back in to make sure they work! ti\njhj

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3i didn't do it, but i can check if you like

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3yeah i get the same thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Don't worry about it, plugging it in will tell me if it's right or not.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3\[f(x) = \left\{\begin{array}{rcc} AxB & \text{if} & x <1 \\ 24x& \text{if} & 1\leq x\leq5\\ Bx^2A&\text{if} &x>5 \end{array} \right. \]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.3just seeing if i could write it \[\color\magenta\heartsuit\]
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