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anonymous

  • one year ago

How to simplify the expression (-3c^3 d^4 e^6) ^2

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  1. Nnesha
    • one year ago
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    hint: \[\huge\rm (x^a y^b)^m = x^{a \times m}y^{b \times m}\]

  2. welshfella
    • one year ago
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    use the rule for exponents - what Nnesha said

  3. anonymous
    • one year ago
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    oh okay so it would be \[-3 c^{6} d ^{8} e ^{12} ?\]

  4. anonymous
    • one year ago
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    cause you would multiply the 2 with all the rest right?

  5. welshfella
    • one year ago
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    doont forget to include the coefficients in your calculations

  6. Nnesha
    • one year ago
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    -3 is raising to the 2nd power as wll

  7. welshfella
    • one year ago
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    (-3)^2 = 9

  8. Nnesha
    • one year ago
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    -3 is same -3^1 \[\rm so (-3^1)^2= (-3)^{1 \times 2}\]

  9. anonymous
    • one year ago
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    well i mean for the coefficients, wouldn't they be the letters?

  10. anonymous
    • one year ago
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    so the answer is 9^2 c^6 d^8 e^12?

  11. anonymous
    • one year ago
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    Cause there are no numbers

  12. Nnesha
    • one year ago
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    that was an example \[\huge\rm (x^a y^b)^m = x^{a \times m}y^{b \times m}\] everything which is inside the parentheses raising to the m power

  13. anonymous
    • one year ago
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    If yes, would the final answer be \[9c^{6} d ^{8} e ^{6}\]

  14. Nnesha
    • one year ago
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    \[\huge\rm (e^6)^2 = e^{??}\]

  15. anonymous
    • one year ago
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    oh i meant e^12

  16. Nnesha
    • one year ago
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    yes right

  17. anonymous
    • one year ago
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    okay thank you

  18. Nnesha
    • one year ago
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    np

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