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anonymous
 one year ago
Tums tablets (contain Calcium Carbonate and other inert substances) when ingested react with gastric juice (HCl) in the stomach to give off CO2(g). When a 1.328 g tablet reacted with 40.00mL HCL (density 1.140g/mL), CO2 was given off and the resulting solution weighed 46.699g. Calculate the number of liters of CO2 was released if it's density is 1.81 g/L.
anonymous
 one year ago
Tums tablets (contain Calcium Carbonate and other inert substances) when ingested react with gastric juice (HCl) in the stomach to give off CO2(g). When a 1.328 g tablet reacted with 40.00mL HCL (density 1.140g/mL), CO2 was given off and the resulting solution weighed 46.699g. Calculate the number of liters of CO2 was released if it's density is 1.81 g/L.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@toxicsugar22 @aaronq

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Abhisar @iambatman can you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Know the chemical equation to this reaction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf CaCO_3 ~(s) + 2HCl~ (aq) \longrightarrow CO_2 ~(g) +CaCl_2 ~(aq)+H_2O~(l)\] given: \[\sf reacted:1.328 \ \ g \ CaCO_3\]\[\sf reacted: 40.00 \ mL \ HCl \times \frac{1.140 ~ g~ HCl}{1 ~ mL~ HCl} = 45.60~ g~ HCl\]\[\sf solution ~ weight ~=46.699~ g\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Empty what do you do with the resulting weight....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Weight of reactantresulting weight=weight of CO2 in g Density is mass/volume. They give you the density of CO2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since carbon dioxide is released then measured

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"Weight of reactants" Forgot the s in reactants in my earlier post.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, well... \[\sf weight~ of ~reactant  resulting ~weight \]\[\sf = (1.328 ~g ~CaCO_3~+~45.60~ g~ HCl) ~ 46.699~g\]\[\sf =46.928~g  46.699~g \]\[\sf = 0.23~ g~ CO_2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sf 0.23 ~g~ CO_2 ~\times \frac{1~L}{1.81~g~CO_2} = 0.127~L ~CO_2 =\boxed{ 0.13~L~CO_2} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea, that is right, but it should be in 3 sf since density of CO2 has the least (3sf) Nice job!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I thought it was based on the lowest # of sf

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ahh, so it must match up to the density of carbon dioxide given.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.13 is 2 sf since, since 0 does not count as a sf 0.127 has 3 sf since 0 does not count as a sf

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the help @jhannybean and @shalante...but how do you know that the resulting weight is all CO2???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\sf CO_2\) is a gas and is the only thing lost after the reaction happens

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{#0cbb34}{\text{Originally Posted by}}\) @Jhannybean Okay, well... \[\sf weight~ of ~reactant  resulting ~weight\]\[\sf = (1.328 ~g ~CaCO_3~+~45.60~ g~ HCl) ~ 46.699~g\]\[\sf =46.928~g  46.699~g\]\[\sf = 0.23~ g~ CO_2\] \(\color{#0cbb34}{\text{End of Quote}}\) This is the initial weight of both reactants when they react minus the weight of the resulting solution (minus the \(\sf CO_2\)); so the weight you get is of the \(\rm CO_2\) lost. Does that make sense?
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