Prove by induction that
3n < n!
when n is an integer and n >= 7.
I have proven that when n=7, the proof is true...
So I did n=k, 3^k < k! then
3^k+1 < (k+1)! I added the term k+1 on both sides...3^k+(k+1) < k! + (k+1). How do go to 3^k+1 < (k+1)! ?

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3^n < n!*

\(k>6\implies 3

where did you get k> 6 from?

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