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AngelaB97
 one year ago
can someone please explain this to me thoroughly because i keep getting confused on how o simplify this expression
AngelaB97
 one year ago
can someone please explain this to me thoroughly because i keep getting confused on how o simplify this expression

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AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1\[(x^2/y^2)^2 (2y^3/x^2)^3\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441669920633:dw

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1it is supposed to be 8/x^10y^13 bu i keep getting 8/x^10y^5

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \left(\frac{x^2}{y^{2}}\right)^{2}\left(\frac{2y^{3}}{x^2}\right)^3\]Change the variables inside the parenthesis so they are all positive. \[\large ( x^2y^2)^{2}\left(\frac{2}{x^2y^3}\right)^3\]Now that we've got all the variables INSIDE the parenthesis with positive powers, now we take care of the outer powers. Take the first one and put it over 1. \[\frac{1}{(x^2y^2)^2}\cdot \left(\frac{2}{x^2y^3}\right)^3\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Now let's distribute the powers through all variables inside the parenthesis. \[\frac{1}{(x^2)^2(y^2)^2} \cdot \frac{2^3}{(x^2)^3(y^3)^3}\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1so since the exponent outside of the parentheses is negative aren't you supposed to flip it so it becomes y^2/x^2 ?

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1r it that where i am making the mistake?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Now let's distribute the powers through all variables inside the parenthesis. \[\frac{1}{(x^2)^2(y^2)^2} \cdot \frac{2^3}{(x^2)^3(y^3)^3}\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1so since the exponent outside of the parentheses is negative aren't you supposed to flip it so it becomes y^2/x^2 ?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Hmm... not exactly. We take care of each step individually.

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1see, its (x^2/y^2) isn't it supposed to be (y^2/x^2)^2

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2So we can write out \(\left(\dfrac{x^2}{y^{2}}\right)^{2}\) as \(\dfrac{1}{\left( \dfrac{x^2}{\dfrac{1}{y^2}}\right)^2}\)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Do you see whats happening here?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2I don't think it's proper to say \(\left(\dfrac{x^2}{y^{2}}\right)^{2} \iff \left(\dfrac{y^2}{x^2}\right)^2\)

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1can you also help me with another problem please?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Are you finished with this one?

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1okay so it's (2y^1z/z^2)^1 (y/3z^2)^2

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2This is a new problem?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2\[\left(\frac{2y^{1}z}{z^2}\right)^{1}\cdot \left(\frac{y}{3z^2}\right)^2\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2So like our previous problem, what will you want to do first?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2No, what do we do to all the negative variables within the parenthesis?

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1we witch them dont we?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2By switch you mean... make them positive? :)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2You are correct. Therefore we will have \[\left(\frac{2z}{yz^2}\right)^{1}\cdot \left(\frac{y}{3z^2}\right)^2\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1yes so then it becomes (yz^2/2z)^1 ?

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1multiplied by (y/3z^2)^2

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1so first you make the numbers inside the parentheses positive, then you flip it whenever there's a negative exponent over the parentheses?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{#0cbb34}{\text{Originally Posted by}}\) @AngelaB97 so first you make the numbers inside the parentheses positive, `then you flip it whenever there's a negative exponent over the parentheses?` \(\color{#0cbb34}{\text{End of Quote}}\) Im not understanding what you mean by that highlighted portion.

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1as in whenever you have a negative exponent both outside and inside the parentheses, you have to deal with the numbers inside the parentheses?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Yes, you deal with the numbers inside the ( ) first, making them + , then we take care of the outside ( ) by putting over 1. [i.e 1/ ( ) ]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Does that make sense?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Cool! \(\checkmark\) Glad you're following along.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Now we have: \[\left(\frac{2z}{yz^2}\right)^{1}\cdot \left(\frac{y}{3z^2}\right)^2\] We're going to put the first one over 1 to make it +. \[\frac{1}{\left(\dfrac{2z}{yz^2}\right)} \cdot \left(\frac{y}{3z^2}\right)^2\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2SOrry, bear with me, Im lagging a lot right now.

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1don't worry you're helping me alot

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2This becomes: \[\frac{yz^2}{2z} \cdot \left(\frac{y}{3z^2}\right)^2\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Now we can reduce our fraction. Remember, \(\dfrac{x^m}{x^n} = x^{mn} \therefore \dfrac{z^2}{z} = z^{21} = z\) Now we can rewrite this as: \[\frac{yz}{2} \cdot \left(\frac{y}{3z^2}\right)^2\]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1then yz/2 * y^2/9z^4

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2We get \[=\frac{y^3z}{18z^4}\] \[\frac{z}{z^4} =z^{14} =z^{3}\] \[=\frac{y^3}{18z^{3}} \iff \boxed{\frac{y^3z^3}{18}}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Whoop whoop wait a minute.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2we got \(z^{3}\) therefore it would be: \[\frac{y^3z^{3}}{18} \iff \boxed{\frac{y^3}{18z^3}} \]

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1gotcha, thanks sosososo much!!! :) <3

AngelaB97
 one year ago
Best ResponseYou've already chosen the best response.1you helped me out so much today

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2No problem :) I've got to head off now. SO good luck on the rest!

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.2Im glad you participated instead of blatantly asking for the answer.
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