anonymous
  • anonymous
An airplane is flying at an altitude of 4,600 ft. The pilot sights an object on the ground at an angle of depression of 35°. What is the slant distance from the airplane to the object ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
|dw:1441671957196:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1441671998905:dw|
jim_thompson5910
  • jim_thompson5910
do you agree with the drawing so far?

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More answers

anonymous
  • anonymous
Yes I do
jim_thompson5910
  • jim_thompson5910
these angles are congruent |dw:1441673560035:dw| since they are alternate interior angles and we have a pair of parallel lines
jim_thompson5910
  • jim_thompson5910
so in a sense, we have this triangle |dw:1441673599603:dw|
jim_thompson5910
  • jim_thompson5910
do you know how to find x ?
anonymous
  • anonymous
no
jim_thompson5910
  • jim_thompson5910
have you learned of trig functions in your lessons?
anonymous
  • anonymous
No, this is a random question given in a summer assignement, I think I may know, but its better to just explain it to me with the steps
jim_thompson5910
  • jim_thompson5910
oh it's part of a summer worksheet? If you don't know the answer, then it's ok to leave it blank. The teacher wants to see where you are in terms of your math skills. If you don't know the answer, then the teacher knows where to focus the lesson. This will avoid him teaching you things you already know.
anonymous
  • anonymous
Still I wanna know, its being counted as a grade
jim_thompson5910
  • jim_thompson5910
that hardly seems fair to ask you a question you haven't learned about yet, and have it graded
jim_thompson5910
  • jim_thompson5910
is this for geometry or trig class?
anonymous
  • anonymous
trig class, pls just answer the question
jim_thompson5910
  • jim_thompson5910
take a look at this chart http://passyworldofmathematics.com/Images/pwmImagesSix/TrigRatiosSeven550x398JPG.jpg which two sides are we using?
anonymous
  • anonymous
adjacent and opp?
jim_thompson5910
  • jim_thompson5910
no, opp and hyp look at the chart again and verify what I'm saying is correct |dw:1441675548088:dw|
jim_thompson5910
  • jim_thompson5910
agreed? or no?
anonymous
  • anonymous
agree
jim_thompson5910
  • jim_thompson5910
which trig function uses opp and hyp together?
anonymous
  • anonymous
sin or soh as in from sohcahtoa
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
so sin(angle) = opp/hyp sin(35) = x/4600
jim_thompson5910
  • jim_thompson5910
using a calculator, what is `sin(35)` equal to?
anonymous
  • anonymous
-0.42818266949
jim_thompson5910
  • jim_thompson5910
make sure you are in degree mode what calculator do you have?
anonymous
  • anonymous
I just use google to calculate it, I dont have a graphing calculator..sorry can you get the result for it
jim_thompson5910
  • jim_thompson5910
use this calculator http://web2.0calc.com/
jim_thompson5910
  • jim_thompson5910
try it again and tell me what you get for the value of `sin(35)`
anonymous
  • anonymous
0.573576436351
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
so `sin(35) = x/4600` is the same as `0.573576436351 = x/4600`
jim_thompson5910
  • jim_thompson5910
at this point, the trig stuff is gone and we have a normal algebraic equation solve for x to get x = ??
anonymous
  • anonymous
-4599.426423563649?
jim_thompson5910
  • jim_thompson5910
idk how you got that
jim_thompson5910
  • jim_thompson5910
what steps did you do to get that?
anonymous
  • anonymous
I think that was wrong, but I have to get x by it self right. So i would need to subtract 4600- 0.573576436351
jim_thompson5910
  • jim_thompson5910
hint: undo division (what operation is the opposite of division?)
anonymous
  • anonymous
multiplication
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
multiply both sides by ________ (fill in the blank)
anonymous
  • anonymous
4600? idk please help
jim_thompson5910
  • jim_thompson5910
yes, multiply both sides by 4600 to isolate x
anonymous
  • anonymous
I got x=2638.4516072146
anonymous
  • anonymous
But thats not one of the options
jim_thompson5910
  • jim_thompson5910
what are your options?
anonymous
  • anonymous
There
1 Attachment
jim_thompson5910
  • jim_thompson5910
oh my bad, I mixed up opp and hyp and I'm just realizing that
jim_thompson5910
  • jim_thompson5910
sin(angle) = opp/hyp sin(35) = 4600/x 0.573576436351 = 4600/x 0.573576436351*x = x*4600/x ... Multiply both sides by x. 0.573576436351*x = 4600 do you see how to isolate x?
anonymous
  • anonymous
in this case use 0.573576436351 to multiply on both sides?
jim_thompson5910
  • jim_thompson5910
you have to undo the multiplication in 0.573576436351*x
anonymous
  • anonymous
please demonstrate
jim_thompson5910
  • jim_thompson5910
what undoes multiplication?
anonymous
  • anonymous
division?
jim_thompson5910
  • jim_thompson5910
yes, you'll divide both sides by _______ (fill in the blank)
anonymous
  • anonymous
0.573576436351?
jim_thompson5910
  • jim_thompson5910
yes, divide both sides by that value
anonymous
  • anonymous
8019.8552598576954158?
jim_thompson5910
  • jim_thompson5910
correct, which rounds to 8019.86
anonymous
  • anonymous
Thanks mate :)
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
Can you help me with this one too: A large totem pole near Kalama, Washington, is 154 ft tall. On a particular day at noon it casts a 198 ft shadow. What is the sun's angle of elevation at that time?
anonymous
  • anonymous
here are the options
1 Attachment
jim_thompson5910
  • jim_thompson5910
are you able to draw a picture of the problem?
anonymous
  • anonymous
I am not, I cannot display it
jim_thompson5910
  • jim_thompson5910
how about on paper? are you able to draw out the triangle?
anonymous
  • anonymous
not really, I have no scanners, no tools on my pc nothing, I can still understand without a photo
jim_thompson5910
  • jim_thompson5910
no I mean just for you to see you can describe the picture to me
jim_thompson5910
  • jim_thompson5910
draw out the triangle and then describe the picture
anonymous
  • anonymous
Yeah I cant see it, cause I dont understand how to draw it sorry
jim_thompson5910
  • jim_thompson5910
try to imagine what it would look like in real life draw a vertical pole, then a shadow. what forms?
anonymous
  • anonymous
okay totem pole at right (154 ft), and a shadow at the back of the pole which is 198 ft , and the sun at the top of pole giving the shadow to pole
jim_thompson5910
  • jim_thompson5910
you should have this |dw:1441679942494:dw|
jim_thompson5910
  • jim_thompson5910
which angle do they want? mark it on my drawing
jim_thompson5910
  • jim_thompson5910
click on the pencil to mark on my drawing
anonymous
  • anonymous
|dw:1441680351616:dw|
anonymous
  • anonymous
that one?
jim_thompson5910
  • jim_thompson5910
it's asking `What is the sun's angle of elevation at that time?` the angle of elevation is actually this angle |dw:1441680645165:dw|
anonymous
  • anonymous
ohh okay
jim_thompson5910
  • jim_thompson5910
look at that chart I posted above which sides are the 154 and 196 with respect to that marked angle?
anonymous
  • anonymous
154=totem, and 198=shadow
jim_thompson5910
  • jim_thompson5910
I meant in terms of opp, hyp, adj
anonymous
  • anonymous
oh my bad, it would be: addj, and opp?
jim_thompson5910
  • jim_thompson5910
yeah let's label our drawing with those |dw:1441680960957:dw|
jim_thompson5910
  • jim_thompson5910
what trig function uses opp and adj?
anonymous
  • anonymous
tan
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
tan(angle) = opp/adj tan(x) = 154/198 I'm making the angle to be x for now
jim_thompson5910
  • jim_thompson5910
now you'll use that calculator I gave you above and type in `arctan(154/198)` the arctan function is the inverse of tangent. It helps find the angles
anonymous
  • anonymous
37.874983651098 ?
jim_thompson5910
  • jim_thompson5910
correct
jim_thompson5910
  • jim_thompson5910
so the angle of elevation is approx 37.87 degrees
anonymous
  • anonymous
ahh okay thanks
jim_thompson5910
  • jim_thompson5910
you're welcome

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