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- Bee_see

Recall that we showed in class that if T is a tree with least 2 vertices, then T contains a leaf. (A
leaf is a vertex of degree one.) Recall also that if T is a tree with leaf x, then T − x is also a tree. (Here,
T − x denotes the tree obtained by deleting x and the edge incident to x from T .)
Prove by induction that if T is a tree, then the number of edges of T is one less than the number of
vertices of T .
(Hint: To start, let P(n) be the proposition that every tree with n vertices has n − 1 edges.)

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- Bee_see

- chestercat

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- thomas5267

What is the definition of tree? If the definition of the tree is chosen to be a connected graph with n vertices and n-1 edges, then the proof is trivial. If the definition of the tree is chosen to be a connected graph with no cycles, then the proof is slightly more complicated.

- Bee_see

what do you mean? is the function p(n)=n-1?

- thomas5267

What definition of tree would you like to use?

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- Bee_see

It's fine. I was able to solve the problem.

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