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anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form.
anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form.

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zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1\(\large x^2+bx+c=(x+\frac{b}{2})^2+c\frac{b^2}{4}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll show you how @zzr0ck3r derived this awesome formula! \[x^28x+3\]\[(x^28x)+3\] \[c=\left(\frac{8}{2}\right)^2 = (4)^2 = 16\] \[(x^28x+16)+316\]\[\boxed{(x4)^213} \iff (x+\frac{b}{2})^2+c\frac{b^2}{4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe not derived... not the right word... but how your function correlates to the formula*
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