anonymous
  • anonymous
Simplify 9 to the 2nd over 9 to the 7th.
Mathematics
katieb
  • katieb
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Nnesha
  • Nnesha
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Nnesha
  • Nnesha
\[\huge\rm \frac{ 9^2 }{ 9^7 }\] when we divide same bases we should ` subtract` exponents \[\huge\rm \frac{ x^m}{ x^n }=x^{m-n}\]
anonymous
  • anonymous
9^5

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Nnesha
  • Nnesha
nope
anonymous
  • anonymous
im not good at math
Nnesha
  • Nnesha
aww you will be an expert \[\huge\rm \frac{ 9^2 }{ 9^7 }=9^{2\color{red}{-}7}\] it should be 2-7
anonymous
  • anonymous
you lost me im sorry
Nnesha
  • Nnesha
we should subtract top exponent from the bottom exponent so it should be 2-7 and \[2-7\cancel{=}5\] sign error!
anonymous
  • anonymous
so it would be 9 to the 5th power right?
Nnesha
  • Nnesha
no 2-7 isn't equal to 5 remember when we subtract if bigger number is negative then answer would be negative !
Nnesha
  • Nnesha
2-3= -1
Nnesha
  • Nnesha
example^
anonymous
  • anonymous
ohh yea im dumb
anonymous
  • anonymous
it would be 9 to the -1
Nnesha
  • Nnesha
nope 2-7 = ???
anonymous
  • anonymous
i mean -5
Nnesha
  • Nnesha
yes right now we need to convert negative to positive exponent so apply this exponent rule \[\huge\rm x^{-m}=\frac{ 1 }{ x^m } \]
Nnesha
  • Nnesha
so \[9^{-5}= ?\]
anonymous
  • anonymous
1/9 to the -5th power omg thx you help alot can you syick around incace i need help again ;-)
Nnesha
  • Nnesha
when we flip the fraction sign would change
Nnesha
  • Nnesha
so 1/9 to the what power ?
anonymous
  • anonymous
-5
Nnesha
  • Nnesha
nope look at this example \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] we don't want negative exponent that's the reason we should flip the fraction
Nnesha
  • Nnesha
so change the sign when you flip it
anonymous
  • anonymous
im really confused
Nnesha
  • Nnesha
i'll give you an example \[\large\rm 3^{-4}=\frac{ 1 }{ 3^4 }\]
anonymous
  • anonymous
ohhhhh 5
Nnesha
  • Nnesha
yes right!
anonymous
  • anonymous
thz you
Nnesha
  • Nnesha
np :=)
anonymous
  • anonymous
Which expression is equivalent to (5^3)^−2? can u help me with this one plzzzzz
Nnesha
  • Nnesha
\[\huge\rm (x^m)^n=x^{m \times n}\] you just need to know exponents rules!
anonymous
  • anonymous
5^-6
Nnesha
  • Nnesha
yes so what about negative e xponents ?
Nnesha
  • Nnesha
what would be ur next step ?
anonymous
  • anonymous
5^6
anonymous
  • anonymous
is that the anwser
Nnesha
  • Nnesha
nope
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha nope look at this example \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] we don't want negative exponent that's the reason we should flip the fraction \(\color{blue}{\text{End of Quote}}\)
anonymous
  • anonymous
this is frustrating idk how to do this
Nnesha
  • Nnesha
\[5^{-6}\] is same as \[9^{-5}\] so how did you changed 9^-5 to positive exponent
anonymous
  • anonymous
would it be1/5^3 juss a ruf guess
Nnesha
  • Nnesha
remember 5 to the -6 power is same as \[\huge\rm \frac{ 5^{-6} }{ 1}\] now flip the fraction and change the sign of the exponent
Nnesha
  • Nnesha
it's 5 to the -6 power not 3
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @copper224 would it be1/5^3 juss a ruf guess \(\color{blue}{\text{End of Quote}}\) 5 to the what power ?
anonymous
  • anonymous
6th im sorry if im frustrating you
anonymous
  • anonymous
i juss suck at math
Nnesha
  • Nnesha
im fine :D
Nnesha
  • Nnesha
well you're in a learning process you will be good at it!
Nnesha
  • Nnesha
alright good luck! practice!!!
anonymous
  • anonymous
In which expression should the exponents be multiplied? one fifth to the 2nd times one fifth to the 6th 9 to the 3rd over 9 to the 4th 73 ⋅ 78 (26)−5
anonymous
  • anonymous

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