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anonymous

  • one year ago

Simplify 9 to the 2nd over 9 to the 7th.

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  1. Nnesha
    • one year ago
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  2. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 9^2 }{ 9^7 }\] when we divide same bases we should ` subtract` exponents \[\huge\rm \frac{ x^m}{ x^n }=x^{m-n}\]

  3. anonymous
    • one year ago
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    9^5

  4. Nnesha
    • one year ago
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    nope

  5. anonymous
    • one year ago
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    im not good at math

  6. Nnesha
    • one year ago
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    aww you will be an expert \[\huge\rm \frac{ 9^2 }{ 9^7 }=9^{2\color{red}{-}7}\] it should be 2-7

  7. anonymous
    • one year ago
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    you lost me im sorry

  8. Nnesha
    • one year ago
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    we should subtract top exponent from the bottom exponent so it should be 2-7 and \[2-7\cancel{=}5\] sign error!

  9. anonymous
    • one year ago
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    so it would be 9 to the 5th power right?

  10. Nnesha
    • one year ago
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    no 2-7 isn't equal to 5 remember when we subtract if bigger number is negative then answer would be negative !

  11. Nnesha
    • one year ago
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    2-3= -1

  12. Nnesha
    • one year ago
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    example^

  13. anonymous
    • one year ago
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    ohh yea im dumb

  14. anonymous
    • one year ago
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    it would be 9 to the -1

  15. Nnesha
    • one year ago
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    nope 2-7 = ???

  16. anonymous
    • one year ago
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    i mean -5

  17. Nnesha
    • one year ago
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    yes right now we need to convert negative to positive exponent so apply this exponent rule \[\huge\rm x^{-m}=\frac{ 1 }{ x^m } \]

  18. Nnesha
    • one year ago
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    so \[9^{-5}= ?\]

  19. anonymous
    • one year ago
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    1/9 to the -5th power omg thx you help alot can you syick around incace i need help again ;-)

  20. Nnesha
    • one year ago
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    when we flip the fraction sign would change

  21. Nnesha
    • one year ago
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    so 1/9 to the what power ?

  22. anonymous
    • one year ago
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    -5

  23. Nnesha
    • one year ago
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    nope look at this example \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] we don't want negative exponent that's the reason we should flip the fraction

  24. Nnesha
    • one year ago
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    so change the sign when you flip it

  25. anonymous
    • one year ago
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    im really confused

  26. Nnesha
    • one year ago
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    i'll give you an example \[\large\rm 3^{-4}=\frac{ 1 }{ 3^4 }\]

  27. anonymous
    • one year ago
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    ohhhhh 5

  28. Nnesha
    • one year ago
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    yes right!

  29. anonymous
    • one year ago
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    thz you

  30. Nnesha
    • one year ago
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    np :=)

  31. anonymous
    • one year ago
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    Which expression is equivalent to (5^3)^−2? can u help me with this one plzzzzz

  32. Nnesha
    • one year ago
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    \[\huge\rm (x^m)^n=x^{m \times n}\] you just need to know exponents rules!

  33. anonymous
    • one year ago
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    5^-6

  34. Nnesha
    • one year ago
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    yes so what about negative e xponents ?

  35. Nnesha
    • one year ago
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    what would be ur next step ?

  36. anonymous
    • one year ago
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    5^6

  37. anonymous
    • one year ago
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    is that the anwser

  38. Nnesha
    • one year ago
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    nope

  39. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha nope look at this example \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\] we don't want negative exponent that's the reason we should flip the fraction \(\color{blue}{\text{End of Quote}}\)

  40. anonymous
    • one year ago
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    this is frustrating idk how to do this

  41. Nnesha
    • one year ago
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    \[5^{-6}\] is same as \[9^{-5}\] so how did you changed 9^-5 to positive exponent

  42. anonymous
    • one year ago
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    would it be1/5^3 juss a ruf guess

  43. Nnesha
    • one year ago
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    remember 5 to the -6 power is same as \[\huge\rm \frac{ 5^{-6} }{ 1}\] now flip the fraction and change the sign of the exponent

  44. Nnesha
    • one year ago
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    it's 5 to the -6 power not 3

  45. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @copper224 would it be1/5^3 juss a ruf guess \(\color{blue}{\text{End of Quote}}\) 5 to the what power ?

  46. anonymous
    • one year ago
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    6th im sorry if im frustrating you

  47. anonymous
    • one year ago
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    i juss suck at math

  48. Nnesha
    • one year ago
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    im fine :D

  49. Nnesha
    • one year ago
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    well you're in a learning process you will be good at it!

  50. Nnesha
    • one year ago
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    alright good luck! practice!!!

  51. anonymous
    • one year ago
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    In which expression should the exponents be multiplied? one fifth to the 2nd times one fifth to the 6th 9 to the 3rd over 9 to the 4th 73 ⋅ 78 (26)−5

  52. anonymous
    • one year ago
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    @nNesha

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