I'm trying to check my answer but it appears wrong based on what the book says. Factors by grouping.
24x^3-36x^2+72X-108
my answer was : (2x-3)(12x^2+36)
please help

- InspectorJoe

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- anonymous

yours in incomplete. 12x + 36 can be factored further by pulling a gcf out

- InspectorJoe

but I did?
here is my problem:

- InspectorJoe

24X^3-36x^2+72X-108
12x2(2X-3)+36(2x-3)
(2x-3)(12x2+36)
???? NOt sure what I did wrong Thanks in advance.

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## More answers

- anonymous

you didn't do anything wrong, it's just that there's another step.
You have (2x - 3)(12x² + 36)
2x - 3 can't be factored anymore
12x² + 36 can have a gcf of 12 factored out

- madhu.mukherjee.946

(2x-3)12(x^2+3)

- anonymous

\[12(2x-3)(x^2+3)\]

- madhu.mukherjee.946

@peachpi thats right:)

- InspectorJoe

So I need to factor my answer which I already had factor previously!
So it's possible that once you have factor a problem your answer my still need to be factor a bit more. ?

- anonymous

yes, that's fairly often the case

- madhu.mukherjee.946

yes.unless you get it in the most simplest form

- madhu.mukherjee.946

remember in these cases you got to reduce the equation to the simplest form

- InspectorJoe

would there had been another way to factor from the start or this would of been the only way which and I would just had to do the extra step at the end ?

- madhu.mukherjee.946

this is the best possible easy way

- InspectorJoe

but my final answer would not match meaning I have a negative and a positive answer. For some reason I though that would be wrong ?

- madhu.mukherjee.946

whats the answer given in your book

- InspectorJoe

The book says the opposite?
= 12(2x-3)(x2+3)

- madhu.mukherjee.946

thats what you have got

- InspectorJoe

this was my original answer:
(2x-3)(12x2+36)

- InspectorJoe

great I just figured it out thanks

- InspectorJoe

would you please take a look at another problem for me?

- madhu.mukherjee.946

say

- InspectorJoe

a^3-3a^2-2a+6
my answer was way off even after changing the - to + and making the - 2a to +(-2a+6)?

- madhu.mukherjee.946

answer will be (a^2-2)(a-3)

- madhu.mukherjee.946

is it okay

- InspectorJoe

that is the answer but can you explain how?

- InspectorJoe

or show

- madhu.mukherjee.946

yes

- madhu.mukherjee.946

a^3-3a^2-2a+6
a^3-2a-3a^2+6
a(a^2-2)-3(a^2-2)
(a-3)(a^2-2)

- madhu.mukherjee.946

did you now understand?

- InspectorJoe

doing the problem myself following your steps....

- madhu.mukherjee.946

go on buddy............:)

- InspectorJoe

sorry but I don't understand why you re- arrange the order when doing factoring by grouping>?

- InspectorJoe

I got the same answer but did not re-arrange the problem

- madhu.mukherjee.946

rearangement makes it more clear and simple

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