InspectorJoe
  • InspectorJoe
I'm trying to check my answer but it appears wrong based on what the book says. Factors by grouping. 24x^3-36x^2+72X-108 my answer was : (2x-3)(12x^2+36) please help
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
yours in incomplete. 12x + 36 can be factored further by pulling a gcf out
InspectorJoe
  • InspectorJoe
but I did? here is my problem:
InspectorJoe
  • InspectorJoe
24X^3-36x^2+72X-108 12x2(2X-3)+36(2x-3) (2x-3)(12x2+36) ???? NOt sure what I did wrong Thanks in advance.

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anonymous
  • anonymous
you didn't do anything wrong, it's just that there's another step. You have (2x - 3)(12x² + 36) 2x - 3 can't be factored anymore 12x² + 36 can have a gcf of 12 factored out
madhu.mukherjee.946
  • madhu.mukherjee.946
(2x-3)12(x^2+3)
anonymous
  • anonymous
\[12(2x-3)(x^2+3)\]
madhu.mukherjee.946
  • madhu.mukherjee.946
@peachpi thats right:)
InspectorJoe
  • InspectorJoe
So I need to factor my answer which I already had factor previously! So it's possible that once you have factor a problem your answer my still need to be factor a bit more. ?
anonymous
  • anonymous
yes, that's fairly often the case
madhu.mukherjee.946
  • madhu.mukherjee.946
yes.unless you get it in the most simplest form
madhu.mukherjee.946
  • madhu.mukherjee.946
remember in these cases you got to reduce the equation to the simplest form
InspectorJoe
  • InspectorJoe
would there had been another way to factor from the start or this would of been the only way which and I would just had to do the extra step at the end ?
madhu.mukherjee.946
  • madhu.mukherjee.946
this is the best possible easy way
InspectorJoe
  • InspectorJoe
but my final answer would not match meaning I have a negative and a positive answer. For some reason I though that would be wrong ?
madhu.mukherjee.946
  • madhu.mukherjee.946
whats the answer given in your book
InspectorJoe
  • InspectorJoe
The book says the opposite? = 12(2x-3)(x2+3)
madhu.mukherjee.946
  • madhu.mukherjee.946
thats what you have got
InspectorJoe
  • InspectorJoe
this was my original answer: (2x-3)(12x2+36)
InspectorJoe
  • InspectorJoe
great I just figured it out thanks
InspectorJoe
  • InspectorJoe
would you please take a look at another problem for me?
madhu.mukherjee.946
  • madhu.mukherjee.946
say
InspectorJoe
  • InspectorJoe
a^3-3a^2-2a+6 my answer was way off even after changing the - to + and making the - 2a to +(-2a+6)?
madhu.mukherjee.946
  • madhu.mukherjee.946
answer will be (a^2-2)(a-3)
madhu.mukherjee.946
  • madhu.mukherjee.946
is it okay
InspectorJoe
  • InspectorJoe
that is the answer but can you explain how?
InspectorJoe
  • InspectorJoe
or show
madhu.mukherjee.946
  • madhu.mukherjee.946
yes
madhu.mukherjee.946
  • madhu.mukherjee.946
a^3-3a^2-2a+6 a^3-2a-3a^2+6 a(a^2-2)-3(a^2-2) (a-3)(a^2-2)
madhu.mukherjee.946
  • madhu.mukherjee.946
did you now understand?
InspectorJoe
  • InspectorJoe
doing the problem myself following your steps....
madhu.mukherjee.946
  • madhu.mukherjee.946
go on buddy............:)
InspectorJoe
  • InspectorJoe
sorry but I don't understand why you re- arrange the order when doing factoring by grouping>?
InspectorJoe
  • InspectorJoe
I got the same answer but did not re-arrange the problem
madhu.mukherjee.946
  • madhu.mukherjee.946
rearangement makes it more clear and simple

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