anonymous
  • anonymous
x^2+4x-5/1-x
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Please Help
madhu.mukherjee.946
  • madhu.mukherjee.946
ok wait
madhu.mukherjee.946
  • madhu.mukherjee.946
is the answer given?

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madhu.mukherjee.946
  • madhu.mukherjee.946
anonymous
  • anonymous
Try and factoring the numerator
madhu.mukherjee.946
  • madhu.mukherjee.946
see you got to middle term breaking the numerator
madhu.mukherjee.946
  • madhu.mukherjee.946
x^2+4x-5 x^+5x-x-5 x(x+5)-1(x+5) (x-1)(x+5)
madhu.mukherjee.946
  • madhu.mukherjee.946
then it becomes(x-1)(x-5)/1-x
anonymous
  • anonymous
Please allow the poster to do some work @madhu.mukherjee.946
madhu.mukherjee.946
  • madhu.mukherjee.946
so now take -1 common -1(1-x)(x+5)/1-x both the 1-x terms cancel so it becomes -x-5=0 sox=-5
anonymous
  • anonymous
I dont understand anything so far, also I have to go offline. Sorry see ya guys
madhu.mukherjee.946
  • madhu.mukherjee.946
omg
madhu.mukherjee.946
  • madhu.mukherjee.946
you don't know middle term breaking

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