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anonymous

  • one year ago

Arthur is trying to find the equation of a perpendicular to y = '1 over 4 x + 4 in slope-intercept form that passes through the point (−2, 6). Which of the following equations will he use? A. y − 6 = 1 over 4 (x − (−2)) B. y − (−2) = 1 over 4 (x − 6) C. y − 6 = −4(x − (−2)) D. y − (−2) = −4(x − 6)

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    the given slope is 1/4 what's the perpendicular slope?

  3. anonymous
    • one year ago
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    I'm not sure.

  4. jim_thompson5910
    • one year ago
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    flip the fraction: 1/4 ----> 4/1 = 4 flip the sign: 4 ----> -4

  5. jim_thompson5910
    • one year ago
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    original slope: +1/4 perpendicular slope: -4/1 or -4

  6. jim_thompson5910
    • one year ago
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    does that seem familiar from the lesson?

  7. anonymous
    • one year ago
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    Yes.

  8. jim_thompson5910
    • one year ago
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    so m = -4

  9. jim_thompson5910
    • one year ago
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    the given point is (x1,y1) = (-2,6)

  10. jim_thompson5910
    • one year ago
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    so we plug these values into the point slope equation \[\Large y - y_1 = m(x-x_1)\] \[\Large y - 6 = -4(x-(-2))\]

  11. anonymous
    • one year ago
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    So is it D?

  12. jim_thompson5910
    • one year ago
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    we could keep going but we can stop here because there is an answer choice that has this

  13. anonymous
    • one year ago
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    I can't tell if it's B or D.

  14. jim_thompson5910
    • one year ago
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    look closely and compare what I have with the choices

  15. jim_thompson5910
    • one year ago
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    hopefully you see how I got that

  16. anonymous
    • one year ago
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    It seems like it's D, am I right?

  17. jim_thompson5910
    • one year ago
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    you mixed up 2 terms. Look closer

  18. anonymous
    • one year ago
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    So it's B?

  19. jim_thompson5910
    • one year ago
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    it sounds like you're randomly guessing

  20. jim_thompson5910
    • one year ago
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    like I said, look for the one that matches with \[\Large y - 6 = -4(x-(-2))\]

  21. anonymous
    • one year ago
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    Ohhh C....I'm sorry my internet wasn't working.

  22. jim_thompson5910
    • one year ago
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    correct

  23. anonymous
    • one year ago
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    Thank you. :)

  24. jim_thompson5910
    • one year ago
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    you're welcome

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