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keana

  • one year ago

HELP! (picture below)

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  1. keana
    • one year ago
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  2. anonymous
    • one year ago
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    Solve for \(C\): \[133 = \dfrac{9}{5} C + 32\] What I did, I used the given Fahrenheit temperature of 133, and substituted its value for the variable \(F\).

  3. keana
    • one year ago
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    ok makes sense

  4. anonymous
    • one year ago
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    If you want I can check your answer if you would like, once you solve for C.

  5. keana
    • one year ago
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    how do i solve for c though...

  6. anonymous
    • one year ago
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    Isolate the like terms to one side of the equation.

  7. keana
    • one year ago
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    alright

  8. anonymous
    • one year ago
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    \[133 = \dfrac{9}{5} C + 32\] \[133 - 32 = \dfrac{9}{5} C\] \[\cdots\] See where I am going, by isolating the like terms?

  9. keana
    • one year ago
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    how do i subtract 9/5 from 133?

  10. anonymous
    • one year ago
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    They are not like terms, so you cannot. Here is an example: \[44 = 3C + 4\] \[\Rightarrow 44 - 4 = 3C\] \[\Rightarrow 40 = 3C\] \[\Rightarrow \dfrac{40}{3} = \dfrac{3C}{3}\] \[\Rightarrow 13.3333... = C\]

  11. keana
    • one year ago
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    so do i subtract 32?

  12. anonymous
    • one year ago
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    Yes, so \(133 - 32 = 101\). \[\Rightarrow 101 = \dfrac{9}{5} C\] \[\Rightarrow \dfrac{101}{1.8} = \dfrac{1.8C}{1.8}\] To understand where I got \(1.8\), I converted the fraction to a decimal. \(\dfrac{9}{5} = 1.8\) All you have to do is simplify now.

  13. keana
    • one year ago
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    i got 56.1111....

  14. anonymous
    • one year ago
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    Correct. \[C \approx 56.111\]

  15. anonymous
    • one year ago
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    Remember your question also asks to round to the nearest tenth.

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