## keana one year ago help! (picture in comments)

1. keana

2. zepdrix

Ok let's see what we know so far...$\large\rm \color{green}{P}=2\color{royalblue}{L}+2\color{orangered}{W}$ They told us that the $$\large\rm \color{green}{\text{perimeter is 212}}$$. So let's plug that in.$\large\rm \color{green}{212}=2\color{royalblue}{L}+2\color{orangered}{W}$

3. zepdrix

They told us that the $$\large\rm \color{royalblue}{\text{Length is two more than the Width}}$$. We can write that relationship like this: $$\large\rm \color{royalblue}{L=W+2}$$

4. keana

yes

5. zepdrix

$\large\rm \color{green}{212}=2\color{royalblue}{(L)}+2\color{orangered}{W}$We plug this information into our equation, replacing L.

6. keana

right

7. zepdrix

$\large\rm \color{green}{212}=2\color{royalblue}{(W+2)}+2\color{orangered}{W}$

8. zepdrix

And from there, you have an equation involving only ONE VARIABLE! :) So you can proceed to solve for W.

9. zepdrix

What do you think? :O

10. keana

lemme work it out

11. keana

212=4w+4?

12. zepdrix

So you ditributed and then combined like-terms? Ya that's a good start! :)

13. keana

52=w?

14. zepdrix

Looks good! And then don't forget about the fact that the $$\large\rm \color{royalblue}{\text{Length is two more than the Width}}$$.

15. keana

so 54?

16. zepdrix

yay good job \c:/

17. keana

thanks!