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keana
 one year ago
help! (picture in comments)
keana
 one year ago
help! (picture in comments)

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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ok let's see what we know so far...\[\large\rm \color{green}{P}=2\color{royalblue}{L}+2\color{orangered}{W}\] They told us that the \(\large\rm \color{green}{\text{perimeter is 212}}\). So let's plug that in.\[\large\rm \color{green}{212}=2\color{royalblue}{L}+2\color{orangered}{W}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1They told us that the \(\large\rm \color{royalblue}{\text{Length is two more than the Width}}\). We can write that relationship like this: \(\large\rm \color{royalblue}{L=W+2}\)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \color{green}{212}=2\color{royalblue}{(L)}+2\color{orangered}{W}\]We plug this information into our equation, replacing L.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \color{green}{212}=2\color{royalblue}{(W+2)}+2\color{orangered}{W}\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And from there, you have an equation involving only ONE VARIABLE! :) So you can proceed to solve for W.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So you ditributed and then combined liketerms? Ya that's a good start! :)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Looks good! And then don't forget about the fact that the \(\large\rm \color{royalblue}{\text{Length is two more than the Width}}\).
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