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anonymous

  • one year ago

Subtract a first degree binomial from a second degree trinomial.

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  1. sweetburger
    • one year ago
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    ax^2 +bx +c -(bx +c) maybe this?

  2. anonymous
    • one year ago
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    \[ax^2 + bx + c - (bx + c)\] would be your answer I believe.

  3. sweetburger
    • one year ago
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    looks good

  4. anonymous
    • one year ago
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    Let \[p_{1}(x)=ax^2+bx+c\] \[p_{2}(x)=dx+e\] \[p_{1}(x)-p_{2}(x)=\Delta p(x)=ax^2+bx+c-(dx+e)=ax^2+(b-d)x+(c-e)\] Special Case: When \[d=b, e=c\] \[\Delta p(x)=ax^2+(b-b)x+(c-c)=ax^2+0x+0=ax^2\] capital Greek letter delta is frequently used to denote a change in 2 quantities I've p(x) as a way to denote polynomials It's another way of writing things, you'll learn along

  5. anonymous
    • one year ago
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    Could you give me a medal please? For best effort?

  6. sweetburger
    • one year ago
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    @160UTurn you just rewrote what i said to be brutally honest

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spraguer (Moderator)
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