Subtract a first degree binomial from a second degree trinomial.

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Subtract a first degree binomial from a second degree trinomial.

Mathematics
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ax^2 +bx +c -(bx +c) maybe this?
\[ax^2 + bx + c - (bx + c)\] would be your answer I believe.
looks good

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Let \[p_{1}(x)=ax^2+bx+c\] \[p_{2}(x)=dx+e\] \[p_{1}(x)-p_{2}(x)=\Delta p(x)=ax^2+bx+c-(dx+e)=ax^2+(b-d)x+(c-e)\] Special Case: When \[d=b, e=c\] \[\Delta p(x)=ax^2+(b-b)x+(c-c)=ax^2+0x+0=ax^2\] capital Greek letter delta is frequently used to denote a change in 2 quantities I've p(x) as a way to denote polynomials It's another way of writing things, you'll learn along
Could you give me a medal please? For best effort?
@160UTurn you just rewrote what i said to be brutally honest

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