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Adi3

  • one year ago

Will medal Please help for f(x)^3 find the simplest form: (i) F(x) + 2

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  1. Adi3
    • one year ago
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    @iambatman

  2. Adi3
    • one year ago
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    @imqwerty

  3. Adi3
    • one year ago
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    @phi

  4. phi
    • one year ago
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    there is not enough info. There must be more to the question.

  5. Adi3
    • one year ago
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    Please help for f(x)^3 find in simplest form: (i) F(x) + 2

  6. anonymous
    • one year ago
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    what is your f(x), what are the other options?

  7. phi
    • one year ago
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    you should post a screen shot of the actual question.

  8. Adi3
    • one year ago
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    fine i will post a scrren shot

  9. Adi3
    • one year ago
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    wait

  10. Adi3
    • one year ago
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  11. Adi3
    • one year ago
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    is this clear enough

  12. Adi3
    • one year ago
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    the first question

  13. anonymous
    • one year ago
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    You should start off by plotting f(x)=x^3 first

  14. Adi3
    • one year ago
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    then

  15. phi
    • one year ago
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    ok, they are saying if you have the curve \[ f(x)= x^3\] write the equation of a new curve, that we get by adding 2: \[ F(x) = x^3 + 2\] and then they want you to graph both curves.

  16. anonymous
    • one year ago
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    Then depending on what you add or subtract from f(x), we can accordingly shift our graph

  17. phi
    • one year ago
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    Do you know how to graph \( y=x^3 \)?

  18. Adi3
    • one year ago
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    yes

  19. Adi3
    • one year ago
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    and @Nishant_Garg how did u do tht

  20. anonymous
    • one year ago
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    graph of x^3 will look something like |dw:1441712835820:dw|

  21. Adi3
    • one year ago
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    how did u do x^3 + 2

  22. Adi3
    • one year ago
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    ths wht the part i m confused in

  23. Adi3
    • one year ago
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    why not 2x^3

  24. anonymous
    • one year ago
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    Now if you add or subtract something from x^3, you just need to shift x^3 by that much on the y axis, if you add 2, shift the graph up by 2 units, if u subtract 3, shift down by 3 units and so on

  25. phi
    • one year ago
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    you plot y= x^3 + 2 by finding (x,y) points and you are doing x^3 + 2 because the formula says f(x)+2 (not 2*f(x))

  26. Adi3
    • one year ago
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    alright i get it yes. who should i medal

  27. phi
    • one year ago
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    x y= x^3 + 2 0 0+2 = 2 1 1 +2 = 3 -1 -1 + 2 = 1 2 8+2=10 -2 -8 +2 = -6 plot the points (-2,-6) (-1,1) (0,2) (1,3) (2,10)

  28. Adi3
    • one year ago
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    i get it thnxs but who should i medal

  29. phi
    • one year ago
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    The whole point of this problem is to see f(x) and f(x)+2 have the same shape, but f(x)+2 is 2 steps above f(x)

  30. Adi3
    • one year ago
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    who should i medal

  31. Adi3
    • one year ago
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    @Nishant_Garg

  32. Adi3
    • one year ago
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    or u

  33. anonymous
    • one year ago
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    It's ok I don't care

  34. phi
    • one year ago
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    the also want you to plot y= x^3 - 3 and it looks like another curve ? they mention 4.

  35. phi
    • one year ago
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    and they want you to figure out if you add +b to the function, it shifts it "up" b steps and -b shifts the function down by b steps

  36. Adi3
    • one year ago
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    its simple x^3 - 3

  37. Adi3
    • one year ago
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    yes

  38. phi
    • one year ago
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    it's simple if you know how to do it.

  39. Adi3
    • one year ago
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    ye

  40. Adi3
    • one year ago
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    ye

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