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anonymous

  • one year ago

x^2+4x-5/1-x

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  1. anonymous
    • one year ago
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    Did you try to factor the numerator?

  2. anonymous
    • one year ago
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    I"m not sure how to, please show me how

  3. anonymous
    • one year ago
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    Factoring is kinda hard for me to figure out

  4. anonymous
    • one year ago
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    ok. start by finding 2 numbers that multiply to -5 and add up 4. What are the factors of 5?

  5. anonymous
    • one year ago
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    What numbers multiply to give 5?

  6. anonymous
    • one year ago
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    5 and 1?

  7. anonymous
    • one year ago
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    alright 5 and 1 multiply to 5. We have -5 in this problem, so either 1 or 5 has to be negative. Which one has to be negative for them to add up to 4?

  8. anonymous
    • one year ago
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    1?

  9. anonymous
    • one year ago
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    right, so the two numbers that multiply to -5 and add to 4 are \(5\) and \(-1\). So we can factor the numerator as \((x + 5)(x-1)\)

  10. anonymous
    • one year ago
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    The denominator can get a -1 factored out and we written as \(-(x-1)\)

  11. anonymous
    • one year ago
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    So then you have \[\frac{ (x+5)(x-1) }{ -(x-1) }\] and you can cancel

  12. anonymous
    • one year ago
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    -(x+5)?

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    Alright back

  15. anonymous
    • one year ago
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    So whats the next step?

  16. anonymous
    • one year ago
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    \(-(x-5)\) is the answer

  17. anonymous
    • one year ago
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    I only have these options?

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  18. anonymous
    • one year ago
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    we got -(x+5) after canceling. distribute the negative to get -x-5

  19. anonymous
    • one year ago
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    thanks

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