anonymous
  • anonymous
x^2+4x-5/1-x
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Did you try to factor the numerator?
anonymous
  • anonymous
I"m not sure how to, please show me how
anonymous
  • anonymous
Factoring is kinda hard for me to figure out

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anonymous
  • anonymous
ok. start by finding 2 numbers that multiply to -5 and add up 4. What are the factors of 5?
anonymous
  • anonymous
What numbers multiply to give 5?
anonymous
  • anonymous
5 and 1?
anonymous
  • anonymous
alright 5 and 1 multiply to 5. We have -5 in this problem, so either 1 or 5 has to be negative. Which one has to be negative for them to add up to 4?
anonymous
  • anonymous
1?
anonymous
  • anonymous
right, so the two numbers that multiply to -5 and add to 4 are \(5\) and \(-1\). So we can factor the numerator as \((x + 5)(x-1)\)
anonymous
  • anonymous
The denominator can get a -1 factored out and we written as \(-(x-1)\)
anonymous
  • anonymous
So then you have \[\frac{ (x+5)(x-1) }{ -(x-1) }\] and you can cancel
anonymous
  • anonymous
-(x+5)?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Alright back
anonymous
  • anonymous
So whats the next step?
anonymous
  • anonymous
\(-(x-5)\) is the answer
anonymous
  • anonymous
I only have these options?
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anonymous
  • anonymous
we got -(x+5) after canceling. distribute the negative to get -x-5
anonymous
  • anonymous
thanks

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