## anonymous one year ago x^2+4x-5/1-x

1. anonymous

Did you try to factor the numerator?

2. anonymous

I"m not sure how to, please show me how

3. anonymous

Factoring is kinda hard for me to figure out

4. anonymous

ok. start by finding 2 numbers that multiply to -5 and add up 4. What are the factors of 5?

5. anonymous

What numbers multiply to give 5?

6. anonymous

5 and 1?

7. anonymous

alright 5 and 1 multiply to 5. We have -5 in this problem, so either 1 or 5 has to be negative. Which one has to be negative for them to add up to 4?

8. anonymous

1?

9. anonymous

right, so the two numbers that multiply to -5 and add to 4 are $$5$$ and $$-1$$. So we can factor the numerator as $$(x + 5)(x-1)$$

10. anonymous

The denominator can get a -1 factored out and we written as $$-(x-1)$$

11. anonymous

So then you have $\frac{ (x+5)(x-1) }{ -(x-1) }$ and you can cancel

12. anonymous

-(x+5)?

13. anonymous

yes

14. anonymous

Alright back

15. anonymous

So whats the next step?

16. anonymous

$$-(x-5)$$ is the answer

17. anonymous

I only have these options?

18. anonymous

we got -(x+5) after canceling. distribute the negative to get -x-5

19. anonymous

thanks