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anonymous

  • one year ago

im suppose to expand using the partial fractions.

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  1. anonymous
    • one year ago
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    \[\frac{ -5x+4 }{ x^2-16 }\]

  2. anonymous
    • one year ago
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    @raiders88

  3. anonymous
    • one year ago
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    Did you factor the denominator?

  4. anonymous
    • one year ago
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    yep x-4 and x-4

  5. anonymous
    • one year ago
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    It's actually (x + 4)(x - 4), from a difference of squares Then you can write this \[\frac{ -5x+4 }{ (x+4)(x-4) }=\frac{ A }{ x+4 }+\frac{ B }{ x-4 }\] Then you have to multiply the whole equation by the denominator on the left side

  6. anonymous
    • one year ago
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    uhh nope it says that there both -'s so idk and the only part i got right n u is the plus in between and the 4's

  7. anonymous
    • one year ago
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    ok, that might have been a mistake in the program. do you want solve it this way since it didn't work that way before.

  8. anonymous
    • one year ago
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    uhh hold up imma look at the video soo il message u when i have a definite answer kk

  9. anonymous
    • one year ago
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    hey uhh try this site https://www.khanacademy.org/math/algebra2/polynomial_and_rational/partial-fraction-expansion/v/partial-fraction-expansion-1

  10. anonymous
    • one year ago
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    no offense, I don't need to try khan academy I know how to do this. Your issue is that you factored the denominator wrong. http://www.wolframalpha.com/input/?i=factor+x%5E2-16

  11. anonymous
    • one year ago
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    ohhh ok ill try this site 2

  12. anonymous
    • one year ago
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    np and foil these out and you'll see \((x-4)(x-4)=x^2-8x+16\) \((x-4)(x+4)=x^2-16\)

  13. anonymous
    • one year ago
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    ok

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