## anonymous one year ago im suppose to expand using the partial fractions.

1. anonymous

$\frac{ -5x+4 }{ x^2-16 }$

2. anonymous

@raiders88

3. anonymous

Did you factor the denominator?

4. anonymous

yep x-4 and x-4

5. anonymous

It's actually (x + 4)(x - 4), from a difference of squares Then you can write this $\frac{ -5x+4 }{ (x+4)(x-4) }=\frac{ A }{ x+4 }+\frac{ B }{ x-4 }$ Then you have to multiply the whole equation by the denominator on the left side

6. anonymous

uhh nope it says that there both -'s so idk and the only part i got right n u is the plus in between and the 4's

7. anonymous

ok, that might have been a mistake in the program. do you want solve it this way since it didn't work that way before.

8. anonymous

uhh hold up imma look at the video soo il message u when i have a definite answer kk

9. anonymous
10. anonymous

no offense, I don't need to try khan academy I know how to do this. Your issue is that you factored the denominator wrong. http://www.wolframalpha.com/input/?i=factor+x%5E2-16

11. anonymous

ohhh ok ill try this site 2

12. anonymous

np and foil these out and you'll see $$(x-4)(x-4)=x^2-8x+16$$ $$(x-4)(x+4)=x^2-16$$

13. anonymous

ok