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anonymous
 one year ago
Find x3  2y2  3x3 + z4 if x = 3, y = 5, and z = 3.
anonymous
 one year ago
Find x3  2y2  3x3 + z4 if x = 3, y = 5, and z = 3.

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Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2x^3  2y^2  3x^3 + z^4  x = 3, y = 5, z = 3 now we sub 3^3  2(5^2)  3(3^3) + (3^4) can you do the math now ?

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.227  2(25)  3(27) + 81 27  50  81  81 212 + 27 185 thats what I got

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2oops..made a mistake on first line...supposed to be 81

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2same answer....185

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2hold on...let me check again 3^3  2(5^2)  3(27) + 81  it is + 81 because 3^4 = 3*3*3*3 = 81 27  50  81 + 81  23 (the 81's cancel each other out)

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.2I am so sorry about that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can i ask you another question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find 3a2  b3 + 3c2  2b3 if a = 2, b = 1, and c = 3.
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