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HowardWolowitz
 one year ago
mean question
HowardWolowitz
 one year ago
mean question

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1using your data, we can write this: \[\Large \frac{{{x_1} + {x_2} + {x_3} + {x_4} + {x_5}}}{5} = 14\] where \( \large x_1,x_2,x_3,x_4,x_5\) are the requested positive numbers Now, if we choose \( \large x_3= 10 \), then we have: \[\Large {x_1},{x_2} < 10,\quad {x_4},{x_5} > 10\] by definition of median

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0I see, but how would you simplify that

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can write this: \[\Large \begin{gathered} {x_1} + {x_2} + 10 + {x_4} + {x_5} = 70 \hfill \\ \hfill \\ \left( {{x_1} + {x_2}} \right) + \left( {{x_4} + {x_5}} \right) = 60 \hfill \\ \end{gathered} \] now I can choose \( \large x_1=5,x_2=9 \) so, what is \( \large x_3+x_4 =...?\)

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0I would tihnk that you couldnt combine

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1if I substitute, I get this: \[\Large {x_4} + {x_5} = 60  9  5 = 46\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so I can choose these values: \[\Large {x_4} = 22,\quad {x_5} = 24\]

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0so is that what you would put to answer the first question?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here are the five positive numbers: \[\Large {x_1} = 5,\quad {x_2} = 9,\quad {x_3} = 10,\quad {x_4} = 22,\quad {x_5} = 24\]

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0ok so i put those and thats it?

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0what about what processi used

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I have used the definition of \( \large median \) and the definition of \( \large mean \) of a distribution of data

HowardWolowitz
 one year ago
Best ResponseYou've already chosen the best response.0I see well ok that makes snese
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