Howard-Wolowitz
  • Howard-Wolowitz
mean question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Howard-Wolowitz
  • Howard-Wolowitz
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Michele_Laino
  • Michele_Laino
using your data, we can write this: \[\Large \frac{{{x_1} + {x_2} + {x_3} + {x_4} + {x_5}}}{5} = 14\] where \( \large x_1,x_2,x_3,x_4,x_5\) are the requested positive numbers Now, if we choose \( \large x_3= 10 \), then we have: \[\Large {x_1},{x_2} < 10,\quad {x_4},{x_5} > 10\] by definition of median
Howard-Wolowitz
  • Howard-Wolowitz
I see, but how would you simplify that

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Michele_Laino
  • Michele_Laino
we can write this: \[\Large \begin{gathered} {x_1} + {x_2} + 10 + {x_4} + {x_5} = 70 \hfill \\ \hfill \\ \left( {{x_1} + {x_2}} \right) + \left( {{x_4} + {x_5}} \right) = 60 \hfill \\ \end{gathered} \] now I can choose \( \large x_1=5,x_2=9 \) so, what is \( \large x_3+x_4 =...?\)
Howard-Wolowitz
  • Howard-Wolowitz
I dont know
Howard-Wolowitz
  • Howard-Wolowitz
I would tihnk that you couldnt combine
Michele_Laino
  • Michele_Laino
if I substitute, I get this: \[\Large {x_4} + {x_5} = 60 - 9 - 5 = 46\]
Michele_Laino
  • Michele_Laino
so I can choose these values: \[\Large {x_4} = 22,\quad {x_5} = 24\]
Howard-Wolowitz
  • Howard-Wolowitz
so is that what you would put to answer the first question?
Michele_Laino
  • Michele_Laino
yes!
Michele_Laino
  • Michele_Laino
here are the five positive numbers: \[\Large {x_1} = 5,\quad {x_2} = 9,\quad {x_3} = 10,\quad {x_4} = 22,\quad {x_5} = 24\]
Howard-Wolowitz
  • Howard-Wolowitz
ok so i put those and thats it?
Michele_Laino
  • Michele_Laino
yes!
Howard-Wolowitz
  • Howard-Wolowitz
alright cool
Howard-Wolowitz
  • Howard-Wolowitz
what about what processi used
Michele_Laino
  • Michele_Laino
I have used the definition of \( \large median \) and the definition of \( \large mean \) of a distribution of data
Howard-Wolowitz
  • Howard-Wolowitz
I see well ok that makes snese

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