I don't know where I went wrong, please help!
The question:
7. The diagram (which I will post a picture of) shows a triangle whose vertices are A(-2,1), B(1,7) and C(3,1). The point L is the foot of the perpendicular line from A to BC, and M is the foot of the perpendicular from B to AC.
(vi) Find the area of the triangle BLH.
So what I did was to find L by finding the midpoint of BC. I got L=(2,4).
Then I found the length of the base, BL, which equaled the square root of 10. I also found the length of the height of the triangle, HL, which equaled the square root of 5.

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That is the triangle given to me. I did not draw my own.

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