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- anonymous

The path of a football kicked by a field goal kicker can be modeled by the equation y = –0.03x2 + 1.53x, where x is the horizontal distance in yards and y is the corresponding height in yards.
Q1: What is the football’s maximum height? Round to the nearest tenth.
Q2: How far is the football kicked?

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- anonymous

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- anonymous

If you have a quadratic function in the form \(y=ax^2+bx+c\) the maximum is at \(x=-\frac{b}{2a}\). Can you tell what your a and b are?

- anonymous

i believe a= -.03 and b=1.53 . but for some reason every time i answer the question it marks it wrong

- anonymous

yes those are right, but -b/(2a) isn't the height. You have to plug what you got for that into the original formula and the y-value you get is the max height

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- anonymous

so you should get \(x=-\frac{1.53}{2(-0.03)}=25.5\).
Then plug in 25.5 for x in the original

- anonymous

oh ok the answer is 19.5 c:

- anonymous

yes.

- anonymous

For the second question, set y = 0 and solve for x. This one factors
\(–0.03x^2 + 1.53x=0\)

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