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anonymous

  • one year ago

What are the solutions to the quadratic equation 4x^2 + 28x = 0?

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  1. anonymous
    • one year ago
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    @Nnesha

  2. anonymous
    • one year ago
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    the options x = 4 and x = −7 x = 4 and x = 7 x = 0 and x = −7 x = 0 and x = 7

  3. Nnesha
    • one year ago
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    would you like to factor it or do you want to use quadratic formula ?

  4. anonymous
    • one year ago
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    quadratic formula

  5. Nnesha
    • one year ago
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    alright then \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\] where a b c are \[\huge\rm Ax^2+Bx+C=0\] a= leading coefficient b=middle term c=constant term substitute

  6. anonymous
    • one year ago
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    so its, 4x^2 + 28x = 0? but theres no c

  7. Nnesha
    • one year ago
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    yes right so substitute c for 0

  8. anonymous
    • one year ago
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    Oh, okay

  9. Nnesha
    • one year ago
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    ye :D

  10. anonymous
    • one year ago
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    Would I plug in those numbers?

  11. Nnesha
    • one year ago
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    yes a= ?? b= ?

  12. anonymous
    • one year ago
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    a=4 and b=28, right

  13. Nnesha
    • one year ago
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    yes right

  14. anonymous
    • one year ago
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    so then the whole equation is 4x^2 +28x +0=0

  15. Nnesha
    • one year ago
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    yes right so substitute a for 4 b for 28 and c for 0

  16. anonymous
    • one year ago
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    ye

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