anonymous
  • anonymous
What are the solutions to the quadratic equation 4x^2 + 28x = 0?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
the options x = 4 and x = −7 x = 4 and x = 7 x = 0 and x = −7 x = 0 and x = 7
Nnesha
  • Nnesha
would you like to factor it or do you want to use quadratic formula ?

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anonymous
  • anonymous
quadratic formula
Nnesha
  • Nnesha
alright then \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\] where a b c are \[\huge\rm Ax^2+Bx+C=0\] a= leading coefficient b=middle term c=constant term substitute
anonymous
  • anonymous
so its, 4x^2 + 28x = 0? but theres no c
Nnesha
  • Nnesha
yes right so substitute c for 0
anonymous
  • anonymous
Oh, okay
Nnesha
  • Nnesha
ye :D
anonymous
  • anonymous
Would I plug in those numbers?
Nnesha
  • Nnesha
yes a= ?? b= ?
anonymous
  • anonymous
a=4 and b=28, right
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
so then the whole equation is 4x^2 +28x +0=0
Nnesha
  • Nnesha
yes right so substitute a for 4 b for 28 and c for 0
anonymous
  • anonymous
ye

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