## anonymous one year ago What are the solutions to the quadratic equation 4x^2 + 28x = 0?

1. anonymous

@Nnesha

2. anonymous

the options x = 4 and x = −7 x = 4 and x = 7 x = 0 and x = −7 x = 0 and x = 7

3. Nnesha

would you like to factor it or do you want to use quadratic formula ?

4. anonymous

5. Nnesha

alright then $\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}$ where a b c are $\huge\rm Ax^2+Bx+C=0$ a= leading coefficient b=middle term c=constant term substitute

6. anonymous

so its, 4x^2 + 28x = 0? but theres no c

7. Nnesha

yes right so substitute c for 0

8. anonymous

Oh, okay

9. Nnesha

ye :D

10. anonymous

Would I plug in those numbers?

11. Nnesha

yes a= ?? b= ?

12. anonymous

a=4 and b=28, right

13. Nnesha

yes right

14. anonymous

so then the whole equation is 4x^2 +28x +0=0

15. Nnesha

yes right so substitute a for 4 b for 28 and c for 0

16. anonymous

ye