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anonymous

  • one year ago

Graph: f(x)=6/(4+x)^2

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  1. campbell_st
    • one year ago
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    well there is a vertical asymptote at x = -4 the value of the graph is always positive since the denominator is squared so there is a horizontal asymptote at y = 0 anything else you need to know...?

  2. campbell_st
    • one year ago
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    oh and it looks a bit like |dw:1441741743820:dw|

  3. anonymous
    • one year ago
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    That's what I got.. I finally figured it out thank you

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spraguer (Moderator)
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