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BloomLocke367

  • one year ago

Homework check?

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  1. BloomLocke367
    • one year ago
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    I got 120 m using sig. figs.

  2. BloomLocke367
    • one year ago
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    @Shalante

  3. anonymous
    • one year ago
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    Sure, can you show your work?

  4. BloomLocke367
    • one year ago
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    yep :)

  5. BloomLocke367
    • one year ago
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    You have to find the final velocity first so you use the formula \(v=v_0+at\). \(v=15m/s+3.5m/s^2(5.0s)\\ v=15m/s+17.5m/s \\ v=32.5m/s\) Then you use the formula \(v^2=v_0~^2+2a(x-x_0)\) (\(32.5m/s)^2=(15m/s)^2+2(3.5m/s^2)(x)\\ 1056.25m^2/s^2=225m^2/s^2+7sec(x)\\ 831.25m^2/s^2=7sec(x)\\ x=118.75m\) so I rounded to 120m.

  6. BloomLocke367
    • one year ago
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    OH MY GOODNESS. I WROTE A WRONG NUMBER.. one second.

  7. BloomLocke367
    • one year ago
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    A car has a velocity of 15 m/s. It then accelerates at a uniform rate of 3.5 m/s^2 for the next 5.0 seconds. What distance does the car cover during this time?

  8. BloomLocke367
    • one year ago
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    that is the right problem.. I looked at the one above it that had 190 lol XD thanks @Shalante for pointing that out

  9. BloomLocke367
    • one year ago
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    @iambatman come back :O

  10. BloomLocke367
    • one year ago
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    okay.. so that took too long to type out.. I'm just going to take pictures of the problems and my work and upload them xD

  11. anonymous
    • one year ago
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    Your process seems fine :)

  12. anonymous
    • one year ago
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    I did not check the numbers however, I trust you're correct :P

  13. BloomLocke367
    • one year ago
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    oh okay. thanks lol

  14. BloomLocke367
    • one year ago
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    Here, I'll close this and you can help with others @Shalante c:

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