Homework check?

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I got 120 m using sig. figs.
Sure, can you show your work?

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Other answers:

yep :)
You have to find the final velocity first so you use the formula \(v=v_0+at\). \(v=15m/s+3.5m/s^2(5.0s)\\ v=15m/s+17.5m/s \\ v=32.5m/s\) Then you use the formula \(v^2=v_0~^2+2a(x-x_0)\) (\(32.5m/s)^2=(15m/s)^2+2(3.5m/s^2)(x)\\ 1056.25m^2/s^2=225m^2/s^2+7sec(x)\\ 831.25m^2/s^2=7sec(x)\\ x=118.75m\) so I rounded to 120m.
OH MY GOODNESS. I WROTE A WRONG NUMBER.. one second.
A car has a velocity of 15 m/s. It then accelerates at a uniform rate of 3.5 m/s^2 for the next 5.0 seconds. What distance does the car cover during this time?
that is the right problem.. I looked at the one above it that had 190 lol XD thanks @Shalante for pointing that out
@iambatman come back :O
okay.. so that took too long to type out.. I'm just going to take pictures of the problems and my work and upload them xD
Your process seems fine :)
I did not check the numbers however, I trust you're correct :P
oh okay. thanks lol
Here, I'll close this and you can help with others @Shalante c:

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