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BloomLocke367
 one year ago
Homework check?
BloomLocke367
 one year ago
Homework check?

This Question is Closed

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2I got 120 m using sig. figs.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sure, can you show your work?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2You have to find the final velocity first so you use the formula \(v=v_0+at\). \(v=15m/s+3.5m/s^2(5.0s)\\ v=15m/s+17.5m/s \\ v=32.5m/s\) Then you use the formula \(v^2=v_0~^2+2a(xx_0)\) (\(32.5m/s)^2=(15m/s)^2+2(3.5m/s^2)(x)\\ 1056.25m^2/s^2=225m^2/s^2+7sec(x)\\ 831.25m^2/s^2=7sec(x)\\ x=118.75m\) so I rounded to 120m.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2OH MY GOODNESS. I WROTE A WRONG NUMBER.. one second.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2A car has a velocity of 15 m/s. It then accelerates at a uniform rate of 3.5 m/s^2 for the next 5.0 seconds. What distance does the car cover during this time?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2that is the right problem.. I looked at the one above it that had 190 lol XD thanks @Shalante for pointing that out

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2@iambatman come back :O

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2okay.. so that took too long to type out.. I'm just going to take pictures of the problems and my work and upload them xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your process seems fine :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did not check the numbers however, I trust you're correct :P

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2oh okay. thanks lol

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.2Here, I'll close this and you can help with others @Shalante c:
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