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You have to find the final velocity first so you use the formula \(v=v_0+at\).
Then you use the formula \(v^2=v_0~^2+2a(x-x_0)\)
so I rounded to 120m.
OH MY GOODNESS. I WROTE A WRONG NUMBER.. one second.
A car has a velocity of 15 m/s. It then accelerates at a uniform rate of 3.5 m/s^2 for the next 5.0 seconds. What distance does the car cover during this time?
that is the right problem.. I looked at the one above it that had 190 lol XD thanks @Shalante for pointing that out
@iambatman come back :O
okay.. so that took too long to type out.. I'm just going to take pictures of the problems and my work and upload them xD
Your process seems fine :)
I did not check the numbers however, I trust you're correct :P
oh okay. thanks lol
Here, I'll close this and you can help with others @Shalante c: