anonymous
  • anonymous
help!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The dot plots below show the test scores of seventh- and eighth-grade students: src="http://learn.flvs.net/webdav/assessment_images/educator_mjmath2_v14/mjmath2_practice_m8_g7_p.jpg" Based on visual inspection of the dot plots, which grade, if any, appears to have the higher mean score? Grade 7 Grade 8 Both groups show about the same mean score. No conclusion about mean score can be made from the data.
Phebe
  • Phebe
@Nnesha
Phebe
  • Phebe
i cant sorry

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Phebe
  • Phebe
i dont even see your dotted line thing it said error
Phebe
  • Phebe
it say cookie error
anonymous
  • anonymous
@markaskingalexandria1
anonymous
  • anonymous
sorry cant help the page u added on ur question keeps saying error
anonymous
  • anonymous
OMG!!
anonymous
  • anonymous
wait do you have kik i cant take a pic and send it to you??
anonymous
  • anonymous
*can
anonymous
  • anonymous
nope i have hangout
anonymous
  • anonymous
what is that?
Phebe
  • Phebe
i got both jus cant get on kik tho
anonymous
  • anonymous
ok im downloading it right now
anonymous
  • anonymous
ok whats your username
anonymous
  • anonymous
@markaskingalexandria1
anonymous
  • anonymous
for hangout
anonymous
  • anonymous
yes
anonymous
  • anonymous
The price of some houses in a neighborhood are shown below: House Price A $120,000 B $130,000 C $140,000 D $150,000 E $1,110,000 Based on the data, should the mean or the median be used to make an inference about the price of the houses in the neighborhood? Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean Median, because it is in the center of the data Mean, because it is in the center of the data
anonymous
  • anonymous
Median, because it is in the center of the data
anonymous
  • anonymous
thank you!!
anonymous
  • anonymous
The following table shows the data collected from a random sample of 100 middle school students on the number of hours they play outdoor games every week: Weekly Duration of Outdoor Games Time (in hours) 0–2 3–5 6–8 9–11 Number of Students 30 62 8 0 There are 1,200 students in the school. Based on the sample proportion, how many students in the school would be expected to play outdoor games for at least three hours every week? 744 840 960 1,104
anonymous
  • anonymous
idk this one
anonymous
  • anonymous
Jack wants to know how many families in his small neighborhood of 60 homes would help organize a neighborhood fund-raising party. He put all the addresses in a bag and drew a random sample of 30 addresses. He then asked those families if they would help organize the fund-raising party. He found that 12% of the families would help organize the party. He claims that 12% of the neighborhood families would be expected to help organize the party. Is this a valid inference? No, this is not a valid inference because he asked only 30 families No, this is not a valid inference because he did not take a random sample of the neighborhood Yes, this is a valid inference because he took a random sample of the neighborhood Yes, this is a valid inference because the 30 families speak for the whole neighborhood
anonymous
  • anonymous
??
anonymous
  • anonymous
Yes, this is a valid inference because he took a random sample of the neighborhood
anonymous
  • anonymous
its still not letting me see it
anonymous
  • anonymous
The following table shows the data collected from a random sample of 100 middle school students on the number of hours they play outdoor games every week: Weekly Duration of Outdoor Games Time (in hours) 0–2 3–5 6–8 9–11 Number of Students 30 62 8 0 There are 1,200 students in the school. Based on the sample proportion, how many students in the school would be expected to play outdoor games for at least three hours every week? 744 840 960 1,104
anonymous
  • anonymous
@MTALHAHASSAN2
anonymous
  • anonymous
@MTALHAHASSAN2 ??
MTALHAHASSAN2
  • MTALHAHASSAN2
yes
anonymous
  • anonymous
the answer..?
MTALHAHASSAN2
  • MTALHAHASSAN2
wait a sec
MTALHAHASSAN2
  • MTALHAHASSAN2
let me think
anonymous
  • anonymous
ok
MTALHAHASSAN2
  • MTALHAHASSAN2
I will say look at 3-5 hours, and the sample is from 100 students, and we have 62 students who play at least 3 - 5 hours a day. So that's 62%, just multiply 1200 by 62%.
anonymous
  • anonymous
so whats the answer
MTALHAHASSAN2
  • MTALHAHASSAN2
i am getting 744 but not sure if is it right or not
anonymous
  • anonymous
ok, i got the same thing
MTALHAHASSAN2
  • MTALHAHASSAN2
i will say plz conform from someone else
MTALHAHASSAN2
  • MTALHAHASSAN2
by the which grade question is it??
anonymous
  • anonymous
huh?
MTALHAHASSAN2
  • MTALHAHASSAN2
@Michele_Laino
Michele_Laino
  • Michele_Laino
the experimental frequency is: 62/100=0.62, so the requested number is: (62/100)*1200=...?
anonymous
  • anonymous
?
Michele_Laino
  • Michele_Laino
the proportion of student which play outdoor games is: 62/100, namely 62 students over 100 students in total
anonymous
  • anonymous
so whats the answer
MTALHAHASSAN2
  • MTALHAHASSAN2
744
anonymous
  • anonymous
ok thanks!! mind helpig me with a few more?
Michele_Laino
  • Michele_Laino
now we have to write that proportion for a sample of 1200 students, so the requested number of students, which play outdorr games, for a sample of 1200 students, is: \[\Large \frac{{62}}{{100}} \cdot 1200 = ...?\]
Michele_Laino
  • Michele_Laino
outdoor*
anonymous
  • anonymous

        Which of the following inferences can be made using the dot plots?
        
         Group X has a higher mean than group Y.
         Group Y has a higher mean than group X.
         There is no overlap between the data.
         The range of each group is different.</div>
        
        
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anonymous
  • anonymous
@Michele_Laino @MTALHAHASSAN2
Michele_Laino
  • Michele_Laino
I'm sorry I see only an error message
MTALHAHASSAN2
  • MTALHAHASSAN2
same

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