A community for students.
Here's the question you clicked on:
 0 viewing
BloomLocke367
 one year ago
more homework check xp
BloomLocke367
 one year ago
more homework check xp

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It requires real effort to look at one line.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I can see it clearly o.o I'm sorryyyyy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I do not want to check your work, but just do the problem. (Hard to see your work as well)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1wait... my work is hard to see.. but I can see the problems XD If you get something different I'll just ask about it lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Only checked the first 2. Lemme see the rest? And do you want me check all the problems?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I would like it.. but you don't have to lol... I think I'm doing a better job than last time with this stuff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Holy sheet. Another worksheet.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1yea.. 19 problems for one night... plus a worksheet from last week that I haven't continued on yet lol (that's the one you helped with last time lol)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1woooo I am getting better XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1you deserve like 50 gazillion medals btw XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1you're awesome omg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04 and 5 are correct.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1hehe thanks xp I don't see why tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06 is correct. 100% on first worksheet. Nice!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey, I forgot to check sf. 1 and 2 are correct but not the right # of sf.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1and he doesn't really care about sig figs right now but thanks c: I try getting them anyways for practice. I'll look and fix it

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.11... 50m/s? that drops it to 1 sig fig.. 2...4.0m/s^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll check the sf at the end. For 3. You can use only one formula to find the answer. \[x _{f}=x _{i}+v _{_{i}}t+\frac{ 1 }{ 2 }at^2\]

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I haven't seen that formula before O.O

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1nevermind.. yes I have XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1but I still got the right answer, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Same goes for 5. 4 is correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait nvm you would still need 2. Your way is faster for 5.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1did I get 3 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're not stuck on 6 right? You are just taking a break?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug in the values to the equation I gave you and it would still be the same with by just using 1 formula.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I'm on 8 right now lol

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I got 1.5m for 6 and 0.13m/s^2

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1well I got the final velocity to be 9.6m/s then I used the formula \(v^2=v_0^2+2a(xx_0)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09.6^2=92.16m 92.16m=0+2(3.2m/s^2)(d) 92.16m/6.4m/s^2=14.4m or 14m when rounded to sf.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can tell your answer is wrong by reading the problem and thinking like this :

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm, if a car accelerate for 3.2m/s^2 for 3 sec straight, wouldn't the distance be more than like around 5m?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It speeds up by 3.2m/s^2 every second

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1OMG I SEE MY MISTAKE

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I didn't square 9.6 lol

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I dunno if I got 8 correct... i got 25m/s after I rounded

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Foe 8, I got the same results.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I'm starting on 9 now

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I got no for 9.. because the final velocity is 5m/s

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For 9, I got no because it would be at 25m/s 0.0

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1that's what I meant lol

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1sorry XD I have issues typing the right numbers for some reason XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1what would I do for 10?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1hang on.. I may be able to figure it out

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1the formula you showed me right..

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1gimme a sec.. everyone is talking

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1you can't add t and t^2, can you?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1OMG I KNOW WHAT TO DO.. I CAN USE THE QUADRATIC FORMULA

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1wait.. I got both negative answers..but it's time.. @Shalante can you walk me through this?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1wait... nevermind xp I graphed it and got 4.. is it 4 seconds?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would need quadratic, which is a pain. So the one formula I told you to use was bad. vf^2=v^i+2ax then vf=vi+at is better.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you are given everything except time in the formula, then it would be a good idea to use that 1 formula.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1ok.. sorry I'm getting stressed

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1ohhh do the two separate ones like I have been?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You got 4 right. Did you do it using 1 formula or 2?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I graphed the quadratic from the first equation you had me use xp

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Either way works but the one formula is annoying since it has a quadratic.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dont do that next time. I messed up also because I hinted you to do it in 1 formula instead of 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0vf^2=v^i+2ax then vf=vi+at

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1bc I tried the quadratic formula but messed up then I just graphed it XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1OMG I FOUND MY MISTAKE AND GOT IT WITH THE QUADRATIC FORMULA :D

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1ok.. idk what to do here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you focusing better right now? Because this question is similar to the ones you done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea I got 3.0 seconds too.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1okay.. time for the next one.. thank you so much by the way XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1for 12.. is 0 the initial velocity and 25 the final?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1oops I forgot x.x

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I got 2083.3m....

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1idk if that's right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but sig figs makes it 2.1 x 10^3m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That means the minimum distance is 2083.3m in order for the train to reach a velocity of 25 m/s. It makes since because the train is accelerating at 0.15 m/s^2

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1then I can move onto precal XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1omg can I just use a ratio for the last one?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 53 }{ 120}=\frac{ 85 }{ x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea, wait after, because I am helping someone on a difficult chem question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No because it does not proportional in that kind of ratio.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0speed 1/distance 1 is not proportional to speed 2/distance 2 Fraction is called a ratio. Meant to write it is not proportional* in the previous post.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1are you sure it's not proportional?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1why isn't it proportional?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, a drag racer can reach a speed of 53 m/s can also mean that when it starts from rest the drag racer can reach a speed of 53 m/s So initial velocity is 0 m/s. Final velocity would be 53 m/s. Distance would be 120m Solve for acceleration using the formula. (Not telling you which formula) But what about 85 m/s. It needs to start from rest in order for the drag racer to move right? Initial velocity is zero, final velocity is 85, acceleration is the one you solved earlier, and distance is what you need to know for the answer.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1um.. don't you need time to find acceleration?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We would use the same acceleration since it is the same drag racer and it told us he had a max acceleration (his highest is 53m/s at 120m)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1\(\large a=\frac{vv_0}{t}\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1right? and we don't have time... wait.. yes we do... v=d/t

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I got 2.26 for the time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why would use that formula when they dont give you the 2 units (time and acceleration) How are you going to solve the unknown variable?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1I think I got this.. I gotta go..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hint: what formula requires distance, initial and final velocity? (Forgot already!?)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Have you made a flashcard with all the kinematic equations on it? If not, I suggest you do, and then either post it on your wall, look at it every day and then see how many you have memorized. Carry the flashcard with you to school as well, and review it every chance you get. The faster you can recall the formulas and how they are applied, the quicker you will finish your test!

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1V^2=V_0^2+2a(xx_0) lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.