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vera_ewing

  • one year ago

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  1. Nnesha
    • one year ago
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    g(n-3) means x =n -3 so substitute all x's for n-3

  2. Nnesha
    • one year ago
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    nope b isn't correct plz show ur steps.

  3. Nnesha
    • one year ago
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    \[\huge\rm \frac{ x^2-2 }{ 5x }\] \[\huge\rm \frac{ (\color{reD}{n-3})^2+2 }{ 5(\color{ReD}{n-3}) }\]

  4. Michele_Laino
    • one year ago
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    I think that B is wrong

  5. Nnesha
    • one year ago
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    remember: \[\huge\rm \color{ReD}{a}(b+c)= \color{reD}{a} \times b + \color{reD}{a} \times c = \color{Red}{a}b+\color{ReD}{a}c\]

  6. Michele_Laino
    • one year ago
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    hint: when we replace x with n-3, the denominator becomes: 5(n-3)=5*n-5*3=...?

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