1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. help please?

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1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. help please?

Mathematics
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The equation for perimeter of a rectangle in terms of length and width is \[P=2l+2w\]
Can you write the length in terms of the width?
|dw:1441745555895:dw|

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it says length is 3 more than twice the width. Write twice the width in terms of w. Then add 3 to it
is the p=2l+2w? or p=2+2w? also how do u write the answer im new at this...
P = 2l + 2w is just a general formula for perimeter of any rectangle. In your rectangle the perimeter is 78, so really your equation is \[2l+2w=78\] Then it says the length is 3 more than twice the width. Twice the width is \(2w\). 3 more than that is \(2w+3\), so that's the length
|dw:1441746101698:dw|
So your whole equation is \[2w+2(2w+3)=78\] and you need to solve that for w

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