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anonymous
 one year ago
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. help please?
anonymous
 one year ago
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. help please?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation for perimeter of a rectangle in terms of length and width is \[P=2l+2w\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you write the length in terms of the width?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441745555895:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it says length is 3 more than twice the width. Write twice the width in terms of w. Then add 3 to it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the p=2l+2w? or p=2+2w? also how do u write the answer im new at this...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P = 2l + 2w is just a general formula for perimeter of any rectangle. In your rectangle the perimeter is 78, so really your equation is \[2l+2w=78\] Then it says the length is 3 more than twice the width. Twice the width is \(2w\). 3 more than that is \(2w+3\), so that's the length

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441746101698:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So your whole equation is \[2w+2(2w+3)=78\] and you need to solve that for w
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