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So for two dices, there are 6*6 = 36 possible combinations right?
how many combinations add up to 4?
1,3 3,1 2,2 there are 3
so for 4, it is 3/36 = 1/12
so you can do the same for 7 and 10 to for (1).
are you saying that there are 6 ways to add up to 6?
yes, so its probability is 1/6
btw how did you get 1/12 for 4?
sorry sorry no there's 5 ways to add up to 6
1,5 2,4 3,3 4,2 5,1
The number is seven my bad
can you explain how you got 3/36 though for 4?
3 combinations to get 4 / all the possible combinations = 3/36.
how is it 36 though
there are 6 possibilities on the first dice & 6 possibilities on the second dice. 6 * 6 = 36
oh never mind. sorry I didn't think about that, I've had a really long day. You are right
oh ok! :D
so in total it should be 6/36+3/36+3/36=12/36=1/3
and for (2), you just have to find the probability that the sum is 12 and subtract it from 1
why subtract one for the sum is 12?
at least 11 is the same as not 12, becuase the biggest sum is 12
right. So that means 11 and 12?
so, "at least 11" refers to sums 2-11. so the only sum that is not considered is 12.
do you get that?
so what you have to do is 1 - (probability of getting 12) = probability of all sums at least 11
so is that mean the answer is 35/36?
it says 35/36 is wrong but the first answer is right
really? :,o let me think I'm sorry...
AHHH I READ THE PROBLEM WRONG... YOU WERE RIGHT IT IS PROBABILITY OF 11 AND 12
so its 1/12
I CAN'T BE MORE SORRY THAN THIS SORRY
dude its alright
That was right
:D thank you very much
thank you :)