Pre-calculus: At a certain time of day, a 15-meter mast casts a 20 meter shadow. What is the angle of elevation of the sun?

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Pre-calculus: At a certain time of day, a 15-meter mast casts a 20 meter shadow. What is the angle of elevation of the sun?

Mathematics
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use the trig ratio to find x \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
@Nnesha So I'm doing tan because I know that the opposite is 15, and the adjacent is 20? And that's my answer? 15/20?

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yes right then use the calculator to find the exact value
I got .75, is that correct? @Nnesha
remember you should inverse tan \[\huge\rm tan( x) =\frac{ 15 }{ 20 }\] \[x= \tan^{-1} \frac{ 15 }{ 20 }\]
find*
@Nnesha So the cotangent....? Sorry I just started pre-calc last week so I'm not sure how to do that.
tan and cot are `reciprocal` not inverse use the calculator to find inverse tan
@Nnesha So tan(15/20) in the calculator?
not tan inverse tan which calculator are u using google or ti84 ?
@Nnesha Oh I figured it out! The final answer is 36.9. Do you mind explaining why I have to find the inverse?
yes that's right tan and invs are opposite like when you have to find side then you should apply tan and when you have to find `an angle ` then you should use invs tan
i found this from mathisfun website http://prntscr.com/8e6m50
https://www.mathsisfun.com/algebra/trig-inverse-sin-cos-tan.html
@Nnesha Thank you SO much. Your help was amazing!
np glad it helped goood work btw! keep it up!

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