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well I know the sum of 8's probability is 5/36
right so wouldn't it be 1/6?
+ the probability of at least 8
so would it be 6/36?
you mean 2/36?
so the answer would be 7/36?
sorry can you forget about what I just said?
for at least one to be a 5 would be 11/36
(for each dice)( 1/6 + 1/6) - 1/36 (because there's a double) = 11/36
so the answer is 11/36?
+ at least 8
- the mutual part
because (5,1)(5,2)(5,3)(3,5)(2,5)(1,5) are included in both probabilities.
oh let me check
I hope that's right.
would it be 7/12? simplified
I did it backwards the sum of being at least 8 would be 17/36
my bad i didn't see the at least 8
ooh so otherwise would it be right?
I think but it would be 22/36= 11/18
ok ok :)
it says not correct
isn't at least 8 = 15/36?
8=5/36, 9=6/36, 10= 3/36, 11=2/36, 12=1/36
9 has 4 combinations
15/36 + 11/36 - 6/36 = 20/36
yes I think 5/9.
I don't get this it says its wrong
:o is this an online thing?
ok try 26/36 then
i only have 2 more attempts
:( I don't get it the events are not mutually excessive so it should be 20/36 but if the test writer is dumb it might be 26/36...
I'm sorry I'm dumb too probably.