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well I know the sum of 8's probability is 5/36

right so wouldn't it be 1/6?

+ the probability of at least 8

so would it be 6/36?

you mean 2/36?

so the answer would be 7/36?

sorry can you forget about what I just said?

yeah

why?

for at least one to be a 5 would be 11/36

(for each dice)( 1/6 + 1/6) - 1/36 (because there's a double) = 11/36

so the answer is 11/36?

+ at least 8

so 11/36+16/36

- the mutual part

-1?

13/18?

-6/36

21/36

why -6/36

because (5,1)(5,2)(5,3)(3,5)(2,5)(1,5) are included in both probabilities.

oh let me check

I hope that's right.

would it be 7/12? simplified

yes

I did it backwards the sum of being at least 8 would be 17/36

my bad i didn't see the at least 8

ooh so otherwise would it be right?

I think but it would be 22/36= 11/18

ok ok :)

it says not correct

:(

isn't at least 8 = 15/36?

how?

8=5/36, 9=6/36, 10= 3/36, 11=2/36, 12=1/36

9 has 4 combinations

your right

26/36

15/36 + 11/36 - 6/36 = 20/36

5/9?

wait wait...

ok

yes I think 5/9.

I don't get this it says its wrong

:o is this an online thing?

yeah

ok try 26/36 then

i only have 2 more attempts

I'm sorry I'm dumb too probably.