• anonymous
A projectile has a mass m and, of course, it is charged (q). The tube, has an electric field E as shown which deflects the projectile as shown. The mass enters the tube with a velocity v (tube length is L) and, due to the electric field, it will be deflected in an upward direction. For a projectile mass of 1.0x10^-10kg, an electric field strength of 1.0x10^6N/C, a plate length of 15mm, and a drop initial horizontal speed of 29m/s, calculate the drop charge necessary to result in a deflection of 1.3mm when it first emerges from the tube.
  • Stacey Warren - Expert
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  • schrodinger
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  • anonymous
  • IrishBoy123
1/ work out the time it takes to pass through plates in **horizontal** direction, time = dist/speed 2/ use equation of motion to find the **vertical** acceleration required in that time for it to rise 1.3mm. \(x = ut + 1/2 at^2\), x = 1.3mm, u = 0, t you have, a you want 3/ \(F = ma = Eq-mg \implies a = E\frac{q}{m} - g\) solve for q

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