a jet plane traveling at 500 mph overtakes a propeller plane traveling at 200 mph that had a 4-hour head start. How far from the starting point are the planes?

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a jet plane traveling at 500 mph overtakes a propeller plane traveling at 200 mph that had a 4-hour head start. How far from the starting point are the planes?

Mathematics
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|dw:1441758591522:dw|
Write the equation that says that the two distances are equal. Solve for t. Use the solution for time to calculate the distance.
500t=200(t+2) @Mertsj

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Other answers:

500t =200(t+4)
|dw:1441759734634:dw|
8/3?
500t = 200t+800 300t=800 t=8/3 d=500t=500(8/3)=1,333 1/3miles
I give up
why do you give up? You found out that in 2 2/3 hours the jet will catch the other plane, right?
I'm trying so hard to do these problems and I can't do it.
Stop saying "can't". You got the time right. If you go 50 miles in one hour, how far will you go in 2 hours?
Answer is 50 times 2
If the jet goes 500 miles in 1 hour, how far will it go in 2 2/3 hours?
I'm on a different question now. It's just stressful.
Answer is 500 time 2 2/3
I know but I'm on A bus traveled on a level road for 3 hours at an average speed 20 miles per hour faster than it traveled on a winding road. The time spent on the winding road was 4 hours. Find the average speed on the level road if the entire trip was 188 miles.
|dw:1441761147881:dw|
This time it tells you the total of the two distances so write and solve the equation that says the sum of the distances is 188
r+20=3(r+20)?
How do you find a sum?
Solve for t?
What is the sum of 3and 5?
8
How did you get that?
property of addition by adding 3 and 5 together
Correct. So I repeat my original question: How do you find a sum?
addition
So back to the problem: What is the sum of the distances?
188?
Look at the table I drew. What is the distance traveled on the level road?
3(r+20)
What is the distance traveled on the winding road?
4r
So the sum is 4r + 3(r+20)
And the problem explains that the total is 188.
Write and solve the equation.
R=120/7
Wouldn't it be 128/7?
\[4r+3(r+20)=188\] \[4r+3r+60=188\] \[7r+60=188\] \[7r=128\] \[r=\frac{128}{7}=18 \frac{2}{7}\]
Oops I meant to put 128/7
That can't be the miles though.
@pooja195 can you help me?

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