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- InspectorJoe

what times # = -20
but when added =- 7?

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- InspectorJoe

what times # = -20
but when added =- 7?

- katieb

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- Nnesha

what are the factors of 20 ?

- InspectorJoe

factors of -20..
I know -5X4 but when I add it does not =-7

- Nnesha

yes right
and when u multiply -2 times -5 you will get 20 but not -20 so `none` are solving quadratic equation ?

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- InspectorJoe

no. here is my problem
3y^2+7y-20=
factors

- Nnesha

i knew it!
leading coefficient isn't one so u should multiply AC

- Nnesha

so first multiply 3 times -20 then find two numbers

- InspectorJoe

oh great yes I got thanks

- anonymous

|dw:1441759651765:dw|

- anonymous

congrats

- Nnesha

remeber for AC method
find two numbers when you multiply them you should get product of AC(a=leading coefficient , c=constant)

- InspectorJoe

i came up with -17

- Nnesha

and do you know you can't write the answer like (x+1st number) (x+2nd number)

- Nnesha

what do you mean `-17`?

- InspectorJoe

I took 3 X -20 to come up with my needed number

- Nnesha

oh no i meant first multiply 3 times -20= which is equal to -60
now find two numbers when you multiply them you should get -60 but when you add or subtract them you should get -7

- Nnesha

+7**

- InspectorJoe

:O(?

- Nnesha

??

- Nnesha

if leading coefficient is one then we still have to multiply A times C but as u know when you multiply by one you will get the same thing
but here leading coefficinet is 3
so multiply a times c = 3 times -20
then find two numbers

- InspectorJoe

right great thanks

- Nnesha

np :=)

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