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anonymous

  • one year ago

A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible? A) 260 hands B) 2,598,960 hands C) 24,380 hands D) 311,875,200 hands

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  1. anonymous
    • one year ago
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    what..

  2. anonymous
    • one year ago
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    52 choose 5 52 C 5 \(\large 52 \choose 5 \)

  3. anonymous
    • one year ago
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    these are different ways to represent the same thing

  4. Mertsj
    • one year ago
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    How many choices for the first card?

  5. anonymous
    • one year ago
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    Are you allowed to use a calculator

  6. anonymous
    • one year ago
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    yea

  7. anonymous
    • one year ago
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    Using a calculator is kind of cheap. Mertsj do you have a different approach

  8. anonymous
    • one year ago
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    you could always use wolfram and type in 52 choose 5

  9. Mertsj
    • one year ago
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    Yes. There are 52 choices for the first card. There are 51 choices for the second card. There are 50 choices for the third card. There are 49 choices for the fourth card. There are 48 choices for the fifth card. So total possible hands are: 52 x 51 x 50 x 49 x 48 = 311,875,200

  10. anonymous
    • one year ago
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    thats an overestimate

  11. anonymous
    • one year ago
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    the order does not count when you receive the 5 cards

  12. anonymous
    • one year ago
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    is it d?

  13. anonymous
    • one year ago
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    its b

  14. Mertsj
    • one year ago
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    It is D

  15. anonymous
    • one year ago
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    example 2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ... the order does not count, so you divide by 5!

  16. Mertsj
    • one year ago
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    Oh yes. The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1

  17. Mertsj
    • one year ago
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    B

  18. anonymous
    • one year ago
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    thanks

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