A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible?
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52 choose 5
52 C 5
\(\large 52 \choose 5 \)
these are different ways to represent the same thing
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How many choices for the first card?
Are you allowed to use a calculator
Using a calculator is kind of cheap.
Mertsj do you have a different approach
you could always use wolfram and type in
52 choose 5
Yes. There are 52 choices for the first card.
There are 51 choices for the second card.
There are 50 choices for the third card.
There are 49 choices for the fourth card.
There are 48 choices for the fifth card.
So total possible hands are:
52 x 51 x 50 x 49 x 48 = 311,875,200
thats an overestimate
the order does not count when you receive the 5 cards
is it d?
It is D
2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ...
the order does not count, so you divide by 5!
Oh yes. The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1