anonymous
  • anonymous
A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible? A) 260 hands B) 2,598,960 hands C) 24,380 hands D) 311,875,200 hands
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what..
anonymous
  • anonymous
52 choose 5 52 C 5 \(\large 52 \choose 5 \)
anonymous
  • anonymous
these are different ways to represent the same thing

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More answers

Mertsj
  • Mertsj
How many choices for the first card?
anonymous
  • anonymous
Are you allowed to use a calculator
anonymous
  • anonymous
yea
anonymous
  • anonymous
Using a calculator is kind of cheap. Mertsj do you have a different approach
anonymous
  • anonymous
you could always use wolfram and type in 52 choose 5
Mertsj
  • Mertsj
Yes. There are 52 choices for the first card. There are 51 choices for the second card. There are 50 choices for the third card. There are 49 choices for the fourth card. There are 48 choices for the fifth card. So total possible hands are: 52 x 51 x 50 x 49 x 48 = 311,875,200
anonymous
  • anonymous
thats an overestimate
anonymous
  • anonymous
the order does not count when you receive the 5 cards
anonymous
  • anonymous
is it d?
anonymous
  • anonymous
its b
Mertsj
  • Mertsj
It is D
anonymous
  • anonymous
example 2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ... the order does not count, so you divide by 5!
Mertsj
  • Mertsj
Oh yes. The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1
Mertsj
  • Mertsj
B
anonymous
  • anonymous
thanks

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