anonymous
  • anonymous
A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are possible? A) 260 hands B) 2,598,960 hands C) 24,380 hands D) 311,875,200 hands
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
what..
anonymous
  • anonymous
52 choose 5 52 C 5 \(\large 52 \choose 5 \)
anonymous
  • anonymous
these are different ways to represent the same thing

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Mertsj
  • Mertsj
How many choices for the first card?
anonymous
  • anonymous
Are you allowed to use a calculator
anonymous
  • anonymous
yea
anonymous
  • anonymous
Using a calculator is kind of cheap. Mertsj do you have a different approach
anonymous
  • anonymous
you could always use wolfram and type in 52 choose 5
Mertsj
  • Mertsj
Yes. There are 52 choices for the first card. There are 51 choices for the second card. There are 50 choices for the third card. There are 49 choices for the fourth card. There are 48 choices for the fifth card. So total possible hands are: 52 x 51 x 50 x 49 x 48 = 311,875,200
anonymous
  • anonymous
thats an overestimate
anonymous
  • anonymous
the order does not count when you receive the 5 cards
anonymous
  • anonymous
is it d?
anonymous
  • anonymous
its b
Mertsj
  • Mertsj
It is D
anonymous
  • anonymous
example 2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ... the order does not count, so you divide by 5!
Mertsj
  • Mertsj
Oh yes. The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1
Mertsj
  • Mertsj
B
anonymous
  • anonymous
thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.