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anonymous
 one year ago
A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different fivecard hands are possible?
A)
260 hands
B)
2,598,960 hands
C)
24,380 hands
D)
311,875,200 hands
anonymous
 one year ago
A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different fivecard hands are possible? A) 260 hands B) 2,598,960 hands C) 24,380 hands D) 311,875,200 hands

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.052 choose 5 52 C 5 \(\large 52 \choose 5 \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these are different ways to represent the same thing

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1How many choices for the first card?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you allowed to use a calculator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using a calculator is kind of cheap. Mertsj do you have a different approach

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you could always use wolfram and type in 52 choose 5

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Yes. There are 52 choices for the first card. There are 51 choices for the second card. There are 50 choices for the third card. There are 49 choices for the fourth card. There are 48 choices for the fifth card. So total possible hands are: 52 x 51 x 50 x 49 x 48 = 311,875,200

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats an overestimate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the order does not count when you receive the 5 cards

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0example 2H 3H 4H 5H 6H = 3H 2H 4H 5H 6H = ... the order does not count, so you divide by 5!

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Oh yes. The order of selection doesn't matter so divide by 5 x 4 x 3 x 2 x 1
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